Answer:
The correct answer is <em>It is a ratio of the concentrations in a reaction.</em>
Explanation:
⇒ It is a ratio of the concentrations in a reaction.
This sentence is true because the equilibrium constant is calculated from the product of the concentration of the reaction products divided into the product of the concentrations of the reactants, each concentration raised by the stoichiometric coefficient. For example, for the following reaction:
aA + bB → cC + dD
The equilibrium constant is expressed as:
![K = \frac{[C]^{c}[D]^{d} }{[A]^{a} [B]^{b} }](https://tex.z-dn.net/?f=K%20%3D%20%5Cfrac%7B%5BC%5D%5E%7Bc%7D%5BD%5D%5E%7Bd%7D%20%20%7D%7B%5BA%5D%5E%7Ba%7D%20%5BB%5D%5E%7Bb%7D%20%7D)
⇒ It remains the same at different temperatures.
The sentence is false because the equilibrium constant changes with the temperature. In general, an endothermic reaction is favored by the increment of temperature (the equilibrium shifts to the right side) and disfavored with the decrease in temperature (shifts to the left).
⇒ It is represented by the symbol H.
This sentence is false because the equilibrium constant is represented with the letter K.
⇒ Its value is always close to 1.
It is not true because the equilibrium constant can be a number below or above 1.
K < 1 ⇒ there is more concentration of reactants at equilibrium
K > 1 ⇒ there is more concentration of products at equilibrium
M= 1 and n = 2
( m+ n = 1 +2 = 3)
rate = K [A] [B]^2
0.2 = K * 3 * 3 ^2
0.2 = K * 3 * 9
K = 0.2 / 27
K = 7.408 * 10 ^ -3 m^-2 s^-1
Bromide ions donates an electron in redox reactions.
<u>Explanation:</u>
- In these redox reactions, the halide ions like bromide donates a pair of electrons and acts as a reducing agents, but itself gets oxidized to bromine.
- In this process, the oxidation state of bromide ion is increased from -1 to 0 oxidation state, that is Br⁻ (-1) to Br₂ (0), thus reduces the compound and oxidizes by itself.
- Bromide ion is a strong reducing agent, thereby reduces sulfuric acid which changes to sulfur di oxide, but this doesn't happen in the case of chloride and fluoride ions as they are not having that much capacity like bromide and iodide ions.
Answer:
answer-
The relative atomic mass = 204.4
explanation:
Thallium -203 = 30%
Thallium -205 = 70%
Therefore ,
relative mass of thallium = (30×203 + 70×205)/100
relative mass of thallium = (20440)/100
relative mass of thallium = 204.40 amu
Thus,
relative atomic mass of thalium =204.4 ( to 1 decimal place)