Answer:
yes
Explanation:
Although plants use photosynthesis to produce glucose, they use cellular respiration to release energy from the glucose.
Aluminum is one of the main factors that reduce plant growth in acid soils. Although it is generally harmful to plants in soils with a neutral medium, the concentration of positive aluminum ions in acid soils increases and malfunctions in root and function growth.
Most acid soils are saturated with aluminum rather than hydrogen ions. Soil acidity is the result of hydrolysis of aluminum compounds. This principle (lime correction) to determine the degree of base saturation in the soil has become the basis of the methods used in soil testing laboratories to determine the lime requirements for soil. Application of lime to soil reduces the toxicity of aluminum to plants. Note This connector loads slowly.
Adaptation of wheat to allow aluminum to be carried out is due to the fact that aluminum releases organic compounds that in turn combine with harmful aluminum cations. It is believed that sorghum has the same endurance. The first genes found to withstand aluminum were found in wheat. Aluminum sulphide bearing has been found to be governed by an individual gene, such as in wheat. This is not the case in all plants.
Answer:
The correct answer is 574.59 grams.
Explanation:
Based on the given information, the number of moles of NH₃ will be,
= 2.50 L × 0.800 mol/L
= 2 mol
The given pH of a buffer is 8.53
pH + pOH = 14.00
pOH = 14.00 - pH
pOH = 14.00 - 8.53
pOH = 5.47
The Kb of ammonia given is 1.8 * 10^-5. Now pKb = -logKb,
= -log (1.8 ×10⁻⁵)
= 5.00 - log 1.8
= 5.00 - 0.26
= 4.74
Based on Henderson equation:
pOH = pKb + log ([salt]/[base])
pOH = pKb + [NH₄⁺]/[NH₃]
5.47 = 4.74 + log ([NH₄⁺]/[NH₃])
log([NH₄⁺]/[NH₃]) = 5.47-4.74 = 0.73
[NH₄⁺]/[NH₃] = 10^0.73= 5.37
[NH₄⁺ = 5.37 × 2 mol = 10.74 mol
Now the mass of dry ammonium chloride required is,
mass of NH₄Cl = 10.74 mol × 53.5 g/mol
= 574.59 grams.
Explanation:
Mass of the organic compound = 200g
Mass of carbon = 83.884g
Mass of hydrogen = 10.486g
Mass of oxygen = 18.640g
The mass of nitrogen = mass of organic compound - (mass of carbon + mass of hydrogen + mass of oxygen)
Mass of nitrogen = 200 - (83.884 + 10.486 + 18.64) = 200 - 113.01
Mass of nitrogen = 86.99g
The empirical formula of a compound is its simplest formula.
It is derived as shown below;
C H O N
Mass 83.884 10.486 18.64 86.99
molar
mass 12 1 16 14
Moles 83.884/12 10.486/1 18.64/16 86.99/14
6.99 10.49 1.17 6.21
Divide
by
lowest 6.99/1.17 10.49/1.17 1.17/1.17 6.21/1.17
6 9 1 5
Empirical formula C₆H₉ON₅
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Empirical formula brainly.com/question/2790794
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Answer: The first steps
Explanation: science
