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earnstyle [38]
3 years ago
15

Question 1 (1 point)

Chemistry
1 answer:
Aneli [31]3 years ago
6 0

Answer:

Question 1. Solubility

Question 2. 18%

Question 3. 60%

Explanation:

Question 1.

Molarity and mass percent are both, sort of concentrations for solutions.

They involve the amount of solute respect to the solution.

Solubility is the ability of a substance to dissolve in another. This capacity can be expressed in moles per liter.

Question 2.

Percent concentration which is also the same as mass percent, shows the mass of solute in 100 g of solution.

In this case, for 18 g of salt which are contained in 100 g of solution, the percent concentration is 18%

Question 3.

Solute: 45 g of sugar

Solvent: 30 g of water

Solution: 75 g of solution

Percent sugar in the solution → (45 g / 75g) . 100 = 60%

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Explanation:

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With all his gear, Neil Armstrong weighed 360 pounds on Earth. When he landed on the Moon, he weighed 60 pounds. Why?
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C. The gravity on the Moon is less than the gravity on Earth.

Explanation:

The weight of Neil Armstrong changed because the gravity on the Moon is less than the gravity on earth. We can infer that the gravity on moon is one-sixth the gravity earth.

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6. Calculate the mass of each product when 100.0 g of CuCl react according to the reaction
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3 years ago
which astronomer supported the belief that earth was at the center of the universe while all other planets and celestial objects
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How many molecules of oxygen are produced when a sample of 38.9 g of water is decomposed by electricity?
statuscvo [17]

Answer:

A) 6.5\times 10^{23}\ \text{molecules}

Explanation:

m = Mass of water = 38.9

M = Molar mass of water = 18 g/mol

N_A = Avogadro's number = 6.022\times 10^{23}\ \text{mol}^{-1}

The reaction of electrolysis would be

2H_2O(l)\rightarrow 2H_2(g)+O_2(g)

Number of moles of H_2O

n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{38.9}{18}\ \text{mol}

From the reaction it can be seen that 2 moles of H_2O gives 1 mole of O_2

So, number of moles of O_2 produced is

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Number of molecules

1.081N_A=1.081\times 6.022\times 10^{23}\\ =6.5\times 10^{23}

So, 6.5\times 10^{23}\ \text{molecules} of oxygen is produced.

8 0
3 years ago
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