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yaroslaw [1]
3 years ago
13

What is H20 and oxygen

Chemistry
2 answers:
olga2289 [7]3 years ago
4 0
H2O means water, which is made of two hydrogen and one oxygen atoms.
Oxygen is a gas that your body needs to function. Oxygen comes from the air.
Vika [28.1K]3 years ago
3 0

Explanation:Hello H2O is water meaning Each water molecule is made of two hydrogen. atoms and one oxygen atom, thus there are two "H" atoms and one. "O". The atoms are joined by covalent bonding.And oxygen is a colorless, odorless reactive gas, the chemical element of atomic number 8 and the life-supporting component of the air.

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What is the organic compound?
kondaur [170]

Answer:

propa-1-nol

Explanation:

easy clapp

3 0
2 years ago
A student reports the following measurements for a set of pennies: 102.0mL, 91.0 g. What is the density of the pennies.
zysi [14]

Answer:

V = 102.0 ml

m = 91.0 ml

density = ...?

density = m / V

= 91.0 / 102.0

= 0.89215 g/ml

7 0
2 years ago
Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili
Katen [24]

<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}

\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M

\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

                         H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>                0.1    0.1

<u>At eqllm:</u>          0.1-x   0.1-x   2x

Evaluating the value of 'x'

\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M

The expression of K_c for above equation follows:

K_c=\frac{[HI]^2}{[H_2][I_2]}

[HI]_{eq}=2x=(2\times 0.079)=0.158M

[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M

[I_2]_{eq}=0.0210M

Putting values in above expression, we get:

K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0
3 years ago
Which chemical formula corresponds to this structural formula?
lys-0071 [83]
I think the answer is choice D
8 0
3 years ago
Read 2 more answers
as 100 milliliters of 0.10 molar KOH is added to 100 milliliters of 0.10 molar HCL at 298 K, the pH of the res?A. decrease to 3B
Mila [183]

Answer:

C. increase to 7.

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

KOH+HCl\rightarrow KCl+H_2O

Thus, the molar relationship is 1 to 1, therefore, the moles are:

n_{HCl}=0.1mol/L*0.1L=0.01molHCl\\n_{KOH}=0.1mol/L*0.1L=0.01molKOH\\

Thus, since the entire hydrogen ions are neutralized, the pH C. increase to 7.

Best regards.

8 0
3 years ago
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