Answer: D) It conducts electricity when it is dissolved in water
<em>What is genetic modification (GM) of crops and how is it done? GM is a technology that involves inserting DNA into the genome of an organism. To produce a GM plant, new DNA is transferred into plant cells. Usually, the cells are then grown in tissue culture where they develop into plants.</em>
Answer:
Theoretical yield =26.03 g
Percent yield = 87%
Limiting reactant = CaO
Explanation:
Given data:
Mass of CaO = 14.4 g
Mass of CO₂ = 13.8 g
Actual yield of CaCO₃ = 22.6 g
Theoretical yield = ?
Percent yield = ?
Limiting reactant = ?
Solution:
Chemical equation:
CaO + CO₂ → CaCO₃
Number of moles of CaO:
Number of moles = Mass /molar mass
Number of moles = 14.4 g / 56.1 g/mol
Number of moles = 0.26 mol
Number of moles of CO₂:
Number of moles = Mass /molar mass
Number of moles = 13.8 g / 44 g/mol
Number of moles = 0.31 mol
Now we will compare the moles of CO₂ and CaO with CaCO₃ .
CO₂ : CaCO₃
1 : 1
0.31 : 0.31
CaO : CaCO₃
1 : 1
0.26 : 0.26
The number of moles of CaCO₃ produced by CaO are less it will be limiting reactant.
Mass of CaCO₃: Theoretical yield
Mass of CaCO₃ = moles × molar mass
Mass of CaCO₃ =0.26 mol × 100.1 g/mol
Mass of CaCO₃ = 26.03 g
Percent yield:
Percent yield = actual yield / theoretical yield × 100
Percent yield = 22.6 g/ 26.03 g × 100
Percent yield = 0.87× 100
Percent yield = 87%
Limiting reactant:
The number of moles of CaCO₃ produced by CaO are less it will be limiting reactant.
1. 2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)
2. 2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)
3. 2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)
<h3>Further explanation</h3>
There are several reactions that can occur in a chemical reaction: single replacement, double replacement, synthesis, decomposition or combustion, etc.
1.Al(s)+HCl(aq)⇒AlCl₃(aq)+H₂(g)
type : single replacement
balance :
2Al(s)+6HCl(aq)⇒2AlCl₃(aq)+3H₂(g)
2. AgNO₃ (aq) + Cu (s) ⇒ Cu(NO₃)₂ (aq) + Ag (s)
type : single replacement
balance :
2AgNO₃ (aq) + Cu (s)⇒Cu(NO₃)₂ (aq) + 2Ag (s)
3. C₃H₈O + O₂ ⇒ CO₂ + H₂O
type : combustion of alcohol
balance :
2C₃H₈O(l) + 9O₂(g) ⇒ 6CO₂(g) + 8H₂O(g)
Answer:
Percentage by mass of oxygen = 76.20% (Approx)
Explanation:
Given:
HNO3
H=1, N=14, O=16]
Find:
Percentage by mass of oxygen
Computation:
HNO3
Total mass = 1 + 14 + 3(16)
Total mass = 63
Mass of oxygen = (3)(16) = 48
Percentage by mass of oxygen = [48/63]100
Percentage by mass of oxygen = 76.20% (Approx)
