<span>Formula: H(t) = 56t – 16t^2
</span>
H(t) = - 16t^2 + 56t
<span><span>A.
</span>What is the height of the ball after 1 second? H
(1) = 56(1) – 16(1) ^2 = 40 pt.</span>
<span><span>B.
</span>What is the maximum height? X = - (56)/2(- 16) =
1.75 sec h (1.75) = 56(1.75) – 16(1.75) ^2 h (1.75) = 49ft.</span>
<span><span>C.
</span><span>After how many seconds will it return to the
ground? – 16t^2 + 56t = 0 - 8t =0 t = 0</span></span>
<span><span>-
</span><span>8t (2 + - 7) = 0 2t – 7 = 0 t = 7/2
Ans: 3.5 seconds</span></span>
This is the answer : plz mark brainlyest
Tables are easy to make when u have the equation. Just simply sub any number in for x and solve for y
y = 3x + 2...lets let x = 0
y = 3(0) + 2
y = 2.....so when x = 0, y = 2....(0,2)
y = 3x + 2....lets let x = 1
y = 3(1) + 2
y = 3 + 2
y = 5....so when x = 1, y = 5....(1,5)
y = 3x + 2.....let x = 2
y = 3(2) + 2
y = 6 + 2
y = 8....so when x = 2, y = 8...(2,8)
u can find more point if u need to...
now make a table..
x y
0 2
1 5
2 8
and like I said, if u need more numbers for ur table, just do like I did above :)
I don’t feel like doing school and I keep getting distracted by this app
1/x^-7
It would look more like 1
------
-7 (as an exponent)
x