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Zolol [24]
3 years ago
11

Calculate the amount of hcn that gives the lethal dose in a small laboratory room measuring 14 × 15 × 8.0ft. the density of air

at 26∘c is 0.00118g/cm3.
Physics
1 answer:
vova2212 [387]3 years ago
7 0
Since we are given the density and volume, then perhaps we can determine the amount in terms of the mass. All we have to do is find the volume in terms of cm³ so that it will cancel out with the cm³ in the density. The conversion is 1 ft = 30.48 cm. The solution is as follows:

V = (14 ft)(15 ft)(8 ft)(30.48 cm/1 ft)³ = 0.0593 cm³

The mass is equal to:
Mass = (0.00118g/cm³)(0.0593 cm³)
Mass = 7 grams of HCN
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A diver makes 1.0 revolutions on the way from a 9.2-m-high platform to the water. Assuming zero initial vertical velocity, find
____ [38]

Answer:

Average angular velocity ≈ 4.59 rad/s

Explanation:

Using the equation of motion,

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making t² the subject of the relation in equation 2,

∴ t² = 2H/g

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∴ t² = ( 2×9.2)/9.8

t = √(2 × 9.2/9.8) = √(18.4/9.8)

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The average angular velocity = θ/t

Where θ = is the number of revolution that the diver makes, t  = time

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Since 1 rev = 2π (rad)

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π = 3.143

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   Average angular velocity ≈ 4.59 rad/s

8 0
3 years ago
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