Both move with constant speed
Answer:
a) 16m/s b) 192m
Explanation:
v1=32m/s a=-2m/s^2 t=8s v2=? d=??
a) I will use this equation v2= v1 + a*t
v2= 32m/s + -2m/s^2 * 8s
v2= 32m/s + -16m/s
v2= 16m/s
b) v2^2=v1^2 + 2ad
rearranging
v2^2-v1^2=2ad
v2^2-v1^2/2= a d
v2^2-v1^2/2a=d
16m/s^2 - 32m/s^2/ 2 x-2m/s^2 =d
d=192m
-- Equations #2 and #6 are both the same equation,
and are both correct.
-- If you divide each side by 'wavelength', you get Equation #4,
which is also correct.
-- If you divide each side by 'frequency', you get Equation #3,
which is also correct.
With some work, you can rearrange this one and use it to calculate
frequency.
Summary:
-- Equations #2, #3, #4, and #6 are all correct statements,
and can be used to find frequency.
-- Equations #1 and #5 are incorrect statements.
Answer:
The distance and average speed are 54.79 m and 10.85 m.
Explanation:
Given that,
Speed = 21.7 m/s
Time = 5.05 s
(a). We need to calculate the distance
Firstly we will find the acceleration
Using equation of motion
Where, v = final velocity
u = initial velocity
t = time
Put the value in the equation
Now, using equation of motion again
For distance,
The distance is 54.79 m.
(b). We need to calculate the average speed during this time
Where, D = total distance
T = time
Put the value into the formula
Hence, The distance and average speed are 54.79 m and 10.85 m.
