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OverLord2011 [107]

3 years ago

6

Please select the word from the list that best fits the definition

2 answers:

Bingel [31]3 years ago

6 0

B. The concave mirror

Tasya [4]3 years ago

5 0

Answer: the answer is B) Concave mirror

Explanation:

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Which of the following would not be found on the electromagnetic spectrum?

kondor19780726 [428]

All wavelengths and frequencies of electromagnetic radiation ...
including visible light ... are features of the electromagnetic spectrum.

Sound waves have nothing to do with the electromagnetic spectrum.

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3 years ago

The atmospheric pressure at normal conditions is equal to 10.33 m under water. Then 1.0mm mercury equals to

mash [69]

Answer:13.6

Explanation:

7 0

4 years ago

Can you access an instance variable from a static method? explain why or why not.

marusya05 [52]

<span>The reason a static method can't access instance variable is because static references the class not a specific instance of the class so there is no instance variable to access.</span>

5 0

4 years ago

What is the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25

alexandr1967 [171]

The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

HOW TO CALCULATE MASS:

The mass of an object can be calculated by dividing the force applied to the object by its acceleration.

According to this question, a bus can accelerate from rest to 15.5 m/s over 8.25s. The acceleration can be calculated as follows:

a = (v - u)/t

a = 15.5 - 0/8.25

a = 15.5/8.25

a = 1.88m/s²

The mass of the bus = 7500N ÷ 1.88m/s²

The mass of the bus = 3989.4kg

Therefore, the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

Learn more about mass at: brainly.com/question/20259048?referrer=searchResults

3 0

3 years ago

In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.

BartSMP [9]

Answer:

The value of g in Kepler-12b is $3.85 m/s^{2}$

Explanation:

To determine the value of g at Kepler-12b it is necessary to combine the equation of the weight and the equation for the Universal law of gravity:

$W = m.g$ (1)

Where m is the mass and g is the value of the gravity

$F = G \frac{M.m}{R^{2}}$ (2)

Equation (1) and equation (2) will be equal, since the weight is a force acting on the object as a consequence of gravity:

$m.g = G \frac{M.m}{R^{2}}$ (3)

Then g will be isolated from equation 3:

$g = G \frac{M.m}{m.R^{2}}$

$g = \frac{G.M}{R^{2}}$ (4)

The radius of Jupiter has a value of 69911000 meters, so its diameter can be determined by:

$d = 2R$ (5)

Where d and R are the diameter and radius of Jupiter

$d_{jupiter} = 2(69911000 m)$

$d_{jupiter} = 139822000 m$

Procedure for finding the radius of Kepler-12b:

For the case of Kepler-12b it has a diameter that is 1.7 times that of Jupiter

$d_{Kepler-12b} = 1.7(d_{jupiter})$

$d_{Kepler-12b} = 1.7(139822000 m)$

$d_{Kepler-12b} = 237697400 m$

By means of equation 5 the radius of Kepler-12b can be known:

$R_{Kepler-12b} = \frac{d}{2}$

$R_{Kepler-12b} = \frac{237697400 m}{2}$

$R_{Kepler-12b} = 118848700 m$

Procedure for finding the mass of Kepler-12b:

The mass of Jupiter has a value of $1.898x10^{27}$ kilograms

For the case of Kepler-12b it has a mass that is 0.43 times that of jupiter

$m_{Kepler-12b} = 0.43(m_{jupiter})$

$m_{Kepler-12b} = 0.43(1.898x10^{27} Kg)$

$m_{Kepler-12b} = 8.161x10^{26} Kg$

The value of g in Kepler-12b can be found by replacing its radius and mass in equation 4:

$g = \frac{(6.67x10^{-11} N.m^{2}/Kg^{2})(8.161x10^{26} Kg)}{(118848700 m)^{2}}$

$g = 3.85 m/s^{2}$

Hence, in Kepler-12b the gravity has a value of $3.85 m/s^{2}$

8 0

3 years ago