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3 years ago

#18-40 evens! please show work! thank you

Mathematics

1 answer:

Dahasolnce [82]3 years ago

5 0

18)k=37
20)q=-17
22)c=-26
24)y=-76
26)r=20
28)n=-15
30)k=25.8
32)n=3.64
34)y=1/8
36)s=-17
38)x=67
40)x=-55

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In FGH, the measure of H=90°, HF=91 feet, and GH = 50 feet. Find the measure of F to the nearest degree.

Rudik [331]

Given:

The angle of H=90°, HF=91 feet, and GH = 50 feet.

The objective is to find the measure of angle F.

In the given right angled triangle, the side opposite to the requierd angle is called opposite side, and the other smaller side is called adjacent side.

The trigonometry formula which relates with the opposite and adjacent side is,

$\tan \theta=\frac{opposite}{adjacent}$

Now substitute the value of opposite and adjacent in the above formula to find the value of angle F.

$\begin{gathered} \tan \theta=\frac{50}{91} \\ \theta=\tan ^{-1}(0.549) \\ \theta=28.787^0 \\ \theta\approx29^0 \end{gathered}$

Hence, the value of angle F is 29 degree.

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Betsy was in a car accident. Her monthly insurance payment of $225 will now be increased by 25%. How much will her monthly payme

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ANSWER FREE BRINLIEST!! ANSWER THE TWOO CIRCLED ONES!!

BlackZzzverrR [31]

Answer:

alright for the first one you set them equal o each other while for the second you do the same thing

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Step-by-step explanation:

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if you want me to clarify more please comment

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san4es73 [151]

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Let v = (v1, v2) be a vector in R2. Show that (v2, −v1) is orthogonal to v, and use this fact to find two unit vectors orthogona

andrey2020 [161]

Answer:

a. v.v' = v₁v₂ - v₁v₂ = 0 b. (20, -21)/29 and (-20,21)/29

Step-by-step explanation:

a. For two vectors a, b to be orthogonal, their dot product is zero. That is a.b = 0.

Given v = (v₁, v₂) = v₁i + v₂j and v' = (v₂, -v₁) = v₂i - v₁j, we need to show that v.v' = 0

So, v.v' = (v₁i + v₂j).(v₂i - v₁j)

= v₁i.v₂i + v₁i.(- v₁j) + v₂j.v₂i + v₂j.(- v₁j)

= v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

i.i = 1, i.j = 0, j.i = 0 and j.j = 1

So, v.v' = v₁v₂i.i - v₁v₁i.j + v₂v₂j.i - v₂v₁j.j

= v₁v₂ × 1 - v₁v₁ × 0 + v₂v₂ × 0 - v₂v₁ × 1

= v₁v₂ - v₂v₁

= v₁v₂ - v₁v₂ = 0

So, v.v' = 0

b. Now a vector orthogonal to the vector v = (21,20) is v' = (20,-21).

So the first unit vector is thus a = v'/║v'║ = (20, -21)/√[20² + (-21)²] = (20, -21)/√[400 + 441] = (20, -21)/√841 = (20, -21)/29.

A unit vector perpendicular to a and parallel to v is b = (-21, -20)/29. Another unit vector perpendicular to b, parallel to a and perpendicular to v is thus a' = (-20,-(-21))/29 = (-20,21)/29

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