Question

Solve for x. (Round your answer to two decimal places) log x = -2

Answer 1

we are given

$log(x)=-2$

we know that

whenever nothing is given in base

we will assume base =10

$log_1_0(x)=-2$

so, we can solve for x

we can take exponent 10 on both sides

$10^{log_1_0(x)}=10^{-2}$

now, log will be cancelled with 10

we get

$x=10^{-2}$

$x=0.01$..............Answer

Answer 2

we are given

log(x)=-2

we know that

whenever nothing is given in base

we will assume base =10

log_1_0(x)=-2

so, we can solve for x

we can take exponent 10 on both sides

10^{log_1_0(x)}=10^{-2}

now, log will be cancelled with 10

we get

x=10^{-2}

x=0.01 ..............Answer