Answer: The price of an adult ticket = $6
The price of a student ticket = $12
Step-by-step explanation:
Let the price of an adult ticket be a
Let the price of a student ticket be b.
From the question,
5a + 14b = 198 ...... equation i
10a + 8b = 156....... equation ii
Multiply equation i by 10
Multiply equation ii by 5
50a + 140b = 1980 ...... equation iii
50a + 40b = 780 ....... equation iv
Subtract iv from iii
100b = 1200
b = 1200/100
b = 12
Put the value of b into equation ii
10a + 8b = 156
10a + 8(12) = 156
10a + 96 = 156
10a = 156-96
10a = 60
a = 6
The price of an adult ticket = $6
The price of a student ticket = $12
there is an error because -9 x 1 = -9 not -1. But I would assume that you multiply -9×-1 and then -9×-2 ect.
A=cost er adult ticket
c=cost per child ticket
2a+14c=96
12a+8c=120
solve
simplify by dividing firs equation by 2 and 2nd by 4
a+7c=48
3a+2c=30
multiply first equaiton by -3 and add to second
-3a-21c=-144
<u>3a+2c=30 +</u>
0a-19c=-114
-19c=-114
divide both sides by -19
x=6
sub back
a+7c=48
6+7c=48
minus 6
7c=42
divide 7
c=6
adult ticket=$6
child ticekt=$6
27 = forty five to the secmventh