Answer:
<em>In the next year, Anthony worked 2,084 hours</em>
Step-by-step explanation:
Anthony worked 1,697 hours in 2010.
We also know Anthony worked 22.8% more hours than in 2010.
The problem requires to calculate how much did Anthony work in the next year.
It can be calculated as follows:
Take 22.8% of 1,697:
Now calculate by adding it to the original number of hours:
1,697 + 387 = 2,084 hours
In the next year, Anthony worked 2,084 hours
Answer:
2/3
Step-by-step explanation:
I hope it helped you
Answer:
C
Step-by-step explanation:
use y=mx+c
follow the flow
<15> and <10> add first 25 <25> and 5 add second 30 <30> and 7 add third 37 <37> and 6 <6> now add that an u get <43> thats ur answer :)
The sequence above is geometric progression.
The nth term of such sequence is given by;
Tn = ar∧(n-1),
Where a⇒first term and
r⇒common ratio
So, 1st term = 5×1.25∧(1-1) = 5×1.25∧0 =5
2nd term = 5×1.25∧(2-1) = 5×1.25 = 6.25
3rd term = 5×1.25∧(3-1) = 5×1.25² = 7.8125
4th term = 5×1.25∧(4-1) =5×1.25³ = 9.765625
5th term = 5×1.25∧(5-1) = 5×1.25∧4 = 12.20703125
6th term = 5×1.25∧(6-1) = 5×1.25∧5 = 15.25878909
