KE = (1/2)·(mass)·(speed)²
KE = (1/2)·(50 kg)·(18 m/s)²
KE = (25 kg)·(324 m²/s²)
KE = 8,100 kg-m²/s²
KE = 8,100 Joules
Speed v = initial speed u + acceleration a x time t
v=u+at = 2 + 4*3 = 14 m/s
Answer:
194516 sheets
Explanation:
So the area of each sheet of paper is:
A = 0.216 * 0.279 = 0.060264 square meters
For the paper sheet to make the same effect as the atmospheric pressure P, then the gravity F from the paper sheet must be
F = AP = 0.060264 * 101325 = 6106 N
Let g = 9.81 m/s2, then the mass of paper needed to generate that gravity is
m = F/g = 6106 / 9.81 = 622.4 kg
If each sheet has a mass of 0.0032 kg, then the total number of sheets to have that much mass is
622.4 / 0.0032 = 194516 sheets
Answer:


Explanation:
d = Diameter of column = 0.5 inch
= Area of concrete = 
The strain in the system is conserved

Now


Stress is given by

The stress in the steel is 

The stress in the steel is 