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dusya [7]
3 years ago
8

While doing bicep curls, Tamara applies 155 Newtons of force to lift the dumbbell. Her forearm is 0.366 meters long and

Physics
1 answer:
katrin2010 [14]3 years ago
8 0

Answer:

54.8 Nm

Explanation:

Torque is the cross product of the radius vector and force vector:

τ = r × F

Another way to write it is the product of the radius and force magnitudes times the sine of the angle between the vectors.

τ = rF sin θ

Here, r = 0.366 meters and F = 155 Newtons.  F is in the +y direction, and r is 15° below the +x axis, so the angle between the vectors is 90° − 15° = 75°.

τ = (0.366 m) (155 N) (sin 75°)

τ = 54.8 Nm

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Sunny_sXe [5.5K]

Answer:

B. 6.00 cm

Explanation:

6 0
3 years ago
The bending of light as it passes into a transparent material of different optical intensity is known as A. conversion. B. aberr
stiks02 [169]

Answer:

<em>D. refraction</em>

Explanation:

Refraction: Refraction is change in direction of light rays. Refraction occurs whenever light rays travels from a transparent medium to another transparent medium of different density. The abrupt change in direction at the surface of the surface of the two media is referred to as <em>refraction</em><em>.</em>

<em>Refraction occurs when light travels from air to glass or from air to liquid.</em>

<em>Laws Of Refraction:</em>

(i) The incident ray, the refracted ray and the normal, all at the point of incident lies in the same plane.

(ii) The ratio of the sine of the angle of incident to the sine of the angle of refraction is a constant for a given pair of media.

<em>Thus the right option is D. refraction</em>

6 0
3 years ago
The component of the external magnetic field along the central axis of a 78-turn circular coil of radius 34.0 cm decreases from
grigory [225]

Answer:

Induced current, I = 18.88 A

Explanation:

It is given that,

Number of turns, N = 78

Radius of the circular coil, r = 34 cm = 0.34 m

Magnetic field changes from 2.4 T to 0.4 T in 2 s.

Resistance of the coil, R = 1.5 ohms

We need to find the magnitude of the induced current in the coil. The induced emf is given by :

\epsilon=-N\dfrac{d\phi}{dt}

Where

\dfrac{d\phi}{dt} is the rate of change of magnetic flux,

And \phi=BA

\epsilon=-NA\dfrac{dB}{dt}

\epsilon=-78\times \pi (0.34)^2\dfrac{(0.4-2.4)}{2}

\epsilon=28.32\ V

Using Ohm's law, \epsilon=I\times R

Induced current, I=\dfrac{\epsilon}{R}

I=\dfrac{28.32}{1.5}

I = 18.88 A

So, the magnitude of the induced current in the coil is 18.88 A. Hence, this is the required solution.

5 0
3 years ago
g typical coffee mug holds up to 12 oz (340 grams) of water. How much heat energy is required to warm enough water from 23⁰C to
Kryger [21]

Answer:

Explanation:

Heat required to raise the temperature

= mass x specific heat x rise in temperature

= .34 x 4200 x ( 95 - 23 )

= 102816 J .

1 kWh = 1000 x 60 x 60 J

= 3600000 J

102816 J  = 102816 / 3600000

= .02856 kWh .

8 0
3 years ago
How far apart (in mm) must two point charges of 70.0 nC (typical of static electricity) be to have a force of 1.30 N between the
Sever21 [200]

Answer:r=5.824 mm

Explanation:

Given

Charge q_1=70 nC

q_2=70 nC

Force between them F=1.30 N

Electrostatic Force is given by

F=\frac{kq_1q_2}{r^2}

where q_1 and q_2 are the charge on the Particles

r=distance between them

k=Coulomb\ constant =9\times 10^9 N-m^2/C^2

1.3=\frac{9\times 10^9\times 70\times 70\times 10^{-18}}{r^2}

r^2=\frac{9\times 10^9\times 70\times 70\times 10^{-18}}{1.3}

r=\sqrt{33.923\times 10^{-6}}

r=5.824\times 10^{-3}

r=5.824 mm

5 0
3 years ago
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