Liquid and solid water were not in the giant gas cloudr
Answer:
a) The angular acceleration of the beam is 0.5 rad/s²CW (direction clockwise due the tangential acceleration is positive)
b) The acceleration of point A is 3.25 m/s²
The acceleration of point E is 0.75 m/s²
Explanation:
a) The relative acceleration of B with respect to D is equal:

Where
aB = absolute acceleration of point B = 2.5 j (m/s²)
aD = absolute acceleration of point D = 1.5 j (m/s²)
(aB/D)n = relative acceleration of point B respect to D (normal direction BD) = 0, no angular velocity of the beam
(aB/D)t = relative acceleration of point B respect to D (tangential direction BD)


We have that
(aB/D)t = BDα
Where α = acceleration of the beam
BDα = 1 m/s²
Where
BD = 2

b) The acceleration of point A is:

(aA/D)t = ADαj

The acceleration of point E is:
(aE/D)t = -EDαj

(1) acceleration, a = 4 m/
(2) acceleration of 10 N,
= 1 m/
and acceleration of 30 N,
= 3 m/
Explanation:
- Here, the acceleration of the object could be found using the equation derived in the second law of motion. The equation is given as, F = ma where m is the acceleration of the object, m is the mass of the object and F is the applied on the object.
- Let
be the acceleration for force 10 N, to find acceleration rearrange the equation to a =
. When we substitute 10 N force and 10 kg mass of the box in the equation. We will get
= 1 m/
- Let
be the acceleration for force 30 N, to find acceleration rearrange the equation to F =
. When we substitute 30 N force and 10 kg mass of the box in the equation. We will get
= 3 m/
- To find the combined, just add the force and substitute in the above equation. Hence, a = 4 m/
