Answer
Given,
Charge, q = 70 A.h
Potential difference, V = 25 V
a) Charge, q = ?
we know that
q= I t
= 70 A.h
= 70 x 60 x 60 A.s
= 252,000 C
b) Potential energy of the charge
U = q V
U = 252,000 x 25
U = 6,300,000 J
<span>Every organism has its own way of making sure its basic needs are met.</span>
<u>A heavy object falls with the acceleration as a light object during free fall because:</u>
Heavy things have a large gravitational force and also have less acceleration. So both the effects exactly cancel and make the falling objects to have the same acceleration irrespective of mass.
Free fall is a unique motion which has only gravitational force that acts on an object. Objects that undergo free fall experience only have the influence of gravity and not any other force.
So when we apply newton's second law of gravity which is:
where,
F is the force
m is the mass
a is the acceleration
For example: When a 1000 kg elephant and a 1 kg rat fall from the same height,
The acceleration can be calculated as follows:
For elephant: F = 10000 N and m = 1000 kg. So,
For rat : F = 10 N and m = 1 kg
Thus,
Hence, it shows that both the animals have the same acceleration irrespective of their mass.
Answer:
V = 0.9 m/s
Explanation:
The parameters given are:
Initial velocity U = 6.4 m/s
Time t = 0.64s
Height h = 2.05 m
To find the final velocity, let us use third equation of motion
V^2 = U^2 - 2gH
Since the ball is going upward, g will be negative
Substitute all the parameters into the formula
V^2 = 6.4^2 - 2 × 9.8 × 2.05
V^2 = 40.96 - 40.18
V^2 = 0.78
V = sqrt( 0.78)
V = 0.883 m/ s
V = 0.9 m/ s approximately
Answer:
Wind the long piece of thin wire around the uniform glass rod multiple times, find the length of the total diameters using the metre ruler, and divide by the number of times you wound it around the rod.
Explanation:
Since the diameter of one long piece of thin wire is too thin to be measured by a metre ruler, you can wind it multiple times and push it side by side to get a length you can measure.
For example, if you wound it around 20 times and the total length of 20 diameters of the wire side-by-side is 2.0 cm, one winding, which is the diameter would be 2.0cm ÷ 20 = 0.10cm or 1mm.