Answer:
H = Vy t - 1/2 g t^2 height of an object with an initial "vertical" velocity
at t sec after firing
Vy = 78 m/s * sin 40 = .643 * 78 m/s = 50.1 m/s
H = 50.1 * 6 - 1/2 * 9.8 * 6^2 = 300 m - 176 m = 124 m
Answer:
The rate at which velocity changes with respect to a change in time is called. acceleration.
Explanation:
Answer:
F=248.5W N
Explanation:
Newton's 2nd Law tells us that F=ma. We will use their averages always. The average acceleration the tennis ball experimented is, by definition:

Since we start counting at 0s and the ball departs from rest, this is just 
So we can write:

Where in the last step we have just multiplied and divided by g, the acceleration of gravity. This allows us to introduce the weight of the ball W since W=gm, so we have:

Substituting our values:

Where the average force exerted has been written it terms of the tennis ball's weight W.
Answer:
0.5m/s2
Explanation:
acceleration= change in velocity/time taken
= v - u/ t
= 10-5/10
=5/10
= 0.5m/s2