Question

Binomial theorem help me solve x^5 Y^8 (x+y)^13

Answer 1

I assume you're asking to find the coefficient of the $x^5y^8$ term in the expansion of $(x+y)^{13}$.

The binomial theorem says that the expansion itself is

$\displaystyle(x+y)^{13}=\sum_{k=0}^{k=13}\binom{13}kx^{13-k}y^k$

and we obtain the $x^5y^8$ term when $k=8$. So the coefficient of this term would be

$\dbinom{13}8=\dfrac{13!}{8!(13-8)!}=1287$