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PtichkaEL [24]
2 years ago
10

Automotive air bags inflate when a sample of Sodium Azide NaN3 is very rapidly decomposed.

Chemistry
1 answer:
Andru [333]2 years ago
6 0

Answer: 1424 grams

Explanation:

2NaN_3\rightarrow 2a+3N_2

Density=\frac{mass}{Volume}

1.25g/L=\frac{mass}{736L}

Mass=920g

Thus mass of nitrogen produced is 920 g.

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

\text{Number of moles of nitrogen}=\frac{920g}{28g/mol}=32.8moles

According to stoichiometry:

3 mole of N_2 are produced from= 2 mole of NaN_3

Thus 32.8 moles of N_2 are produced from=\frac{2}{3}\times 32.8=21.9moles of NaN_3

Mass of NaN_3=moles\times {\text {molar mass}}=21.9\times 65=1424g

Thus 1424 grams of sodium azide is required to produce 736 L of Nitrogen gas with the density of 1.25 g/L.

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The ecosystem services provided by the each of the given examples are as follows:

  • A cornfield in Kansas provides provisioning services.
  • Bacteria that decompose waste along the Gulf Coast provides regulating services.
  • Ocean currents that keep Pacific Northwest air cool and moist provides regulating services.
  • Flower garden at a national landmark provides cultural services.
  • Lumber from an oak tree provides provisioning services.
  • Animals that eat seeds and then spread the seeds through their waste regulating services.

<h3>Ecosystem services</h3>

Ecosystem services are defined as the benefits derived by man from the surroundings ecosystems.

<h3>Categories of ecosystem services</h3>

The four categories of ecosystem services are:

  • regulating services,
  • provisioning services,
  • cultural services, and
  • supporting services

A cornfield in Kansas provides provisioning services.

Bacteria that decompose waste along the Gulf Coast provides regulating services.

Ocean currents that keep Pacific Northwest air cool and moist provides regulating services.

Flower garden at a national landmark provides cultural services.

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Learn more about ecosystem services at: brainly.com/question/2191258

7 0
2 years ago
True or False: Water is a liquid at – 5 °C.
Lilit [14]

Answer:

False

Explanation:

8 0
2 years ago
Read 2 more answers
How many molecules of O2 are in 153.9 g O2?
MrRissso [65]

Answer:

2.895*10^24

Explanation:

mass of Oxygen give = 153.9g

molar mass of O2 molecule = 16*2=32g/mol

n= mole

To find the mole

n= mass/ molar mass

n= 153.9/32

n=4.81mol.

To find the number of molecules of o

Nm= number of molecule

Nn = Number of mole

NA = number of Avogados

Nm= Nn * NA

Nm= 4.81 *6.02*10^23

Nm= 2.895*10^24

3 0
2 years ago
An aqueous solution containing 9.82 g9.82 g of lead(II) nitrate is added to an aqueous solution containing 5.76 g5.76 g of potas
n200080 [17]

Answer:

  • The limiting reactant is lead(II) nitrate.
  • 7.20 g of precipitate are formed.
  • 1.9 g of the excess reactant remain.

Explanation:

The reaction that takes place is:

  • Pb(NO₃)₂(aq) + 2KCl(aq) → PbCl₂(s) + 2KNO₃(aq)

With a percent yield of 87.5%.

To determine the limiting reactant, first we <u>convert the masses of each reactant to moles</u>, using their molar mass:

  • 9.82 g Pb(NO₃)₂ ÷ 331.2 g/mol = 0.0296 mol Pb(NO₃)₂
  • 5.76 g KCl ÷ 74.55 g/mol = 0.0773 mol KCl

Looking at the stoichiometric coefficients, we see that 1 mol of Pb(NO₃)₂ would react completely with 2 moles of KCl. Following that logic, 0.0296 mol Pb(NO₃)₂ would react completely with (2x0.0296) 0.0592 mol of KCl. We have more than that amount of KCl, this means KCl is the reactant in excess and Pb(NO₃)₂ is the limiting reactant.

To calculate the mass of precipitate (PbCl₂) formed, we <u>use the moles of the limiting reactant</u>:

  • 0.0296 mol Pb(NO₃)₂ \frac{1molPbCl_{2}}{1molPb(NO_{3})_{2}} * \frac{278.1g}{1molPbCl_{2}} * 87.5/100 = 7.20 g PbCl₂

- Keeping in mind the reaction yield, the moles of Pb(NO₃)₂ that would react are:

  • 0.0296 mol Pb(NO₃)₂ * 87.5/100 = 0.0259 mol Pb(NO₃)₂

Now we <u>convert that amount to moles of KCl and finally into grams of KCl</u>:

  • 0.0259 mol Pb(NO₃)₂ \frac{2molKCl}{1molPb(NO_{3})_2} * \frac{74.55g}{1molKCl} = 3.86 g KCl

3.86 g of KCl would react, so the amount remaining would be:

  • 5.76 - 3.86 = 1.9 g KCl

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3 years ago
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false

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