On the lewis dot diagram What element reacts simiar to clorine

muminat

1 molecule of glucose contains 6 atoms of C, 12 atoms of H , and 6 atoms of 0.1 mole of glucose contains 6 moles of C atoms , 12 moles of H atoms , and 6 moles of O atoms .

6 0

3 years ago

Which statement best explains why magnesium and chlorine combine in a 1:2 ratio?

denpristay [2]

The statement that best explains why magnesium and chlorine combine in a 1:2 ratio is; Magnesium has two valence electrons, and chlorine can accept one electron in its outer shell.

The number of electrons that an atom of an element has in its outermost shell determines the chemical formula of the compounds formed by atoms such elements.

Magnesium is in group 2, as such it has two electrons in its outermost shell while chlorine in group 17 only accepts one electron in its outermost shell. This one electron will give chlorine an inert gas configuration while the loss of two electrons give magnesium an inert gas configuration.

Therefore; The compound MgCl2 is formed in the ratio of 1:2 because Magnesium has two valence electrons, and chlorine can accept one electron in its outer shell.

Learn more: brainly.com/question/11527546

8 0

2 years ago

Which of these statements explains the relationship among elements, compounds, and mixtures?

gladu [14]

A compound is where two or more elements have chemically bonded, and a mixture is where there are two or more elements are grouped together, but they are not chemically bonded.
An example of a mixture would be salt dissolved in water, and an example of a compound would be water (which is made up of 2 Hydrogen and 1 Oxygen bonded together)

tl;dr: I would go with B, basically.

6 0

3 years ago

___CH4 + ___O2 → ___CO2 + ___H2O When you burn natural gas in the laboratory, methane burns. What numbers fill in the blanks to

Hitman42 [59]

Answer:

The coefficient are 1,2,1,2 ( option B is correct)

Explanation:

Step 1: Data given

Methane = CH4

Burning methane = CH4 + O2

Step 2: The unbalanced equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

Step 3: Balancing the equation

CH4(g) + O2(g) → CO2(g) + H2O(g)

On the left side we have 4x H (in CH4), on the right side we have 2x H (in H2O). To balance the amount of H, on both sides, we have to multiply H2O (on the right side by 2).

CH4(g) + O2(g) → CO2(g) + 2H2O(g)

On the left side we have 2x O (in O2), on the right side we have 4x O (2x in CO2 and 2x in 2H2O). To balance the amount of O on both sides, we have to multiply O2 (on the left side by 2).

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

The coefficient are 1,2,1,2 ( option B is correct)

3 0

2 years ago

A sample of ideal gas at room temperature occupies a volume of 12.0 L at a pressure of 802 torr . If the pressure changes to 401

Blababa [14]

The new volume is 2.4 L

<u><em> calculation</em></u>

The new volume is calculated using Boyle's law formula

That is P₁V₁=P₂V₂

where,

p₁ = 802 torr

V₁ = 12.0 l

P₂ = 4010 torr

V₂=?

make V₂ the subject of the formula by diving both side of equation by P₂

V₂ = P₁V₁/P₂

V₂ is therefore = {(12.0 l × 802 torr) 4010 torr} = 2.4 L

7 0

3 years ago