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Licemer1 [7]
3 years ago
8

For an exothermic reaction at equilibrium, how will increasing the temperature affect Keq?

Chemistry
1 answer:
Sonja [21]3 years ago
8 0

Question:

<em>For an exothermic reaction at equilibrium, how will increasing the temperature affect Keq?</em>

Answer:

<em>The reaction will proceed towards the liquid phase. Heat is on the reactant side of the equation. Lowering temperature will shift equilibrium left, creating more liquid water. A reaction that is exothermic releases heat, while an endothermic reaction absorbs heat.</em>

<em>If you increase the temperature, the position of equilibrium will move in such a way as to reduce the temperature again. It will do that by favouring the reaction which absorbs heat. In the equilibrium, that will be the back reaction because the forward reaction is exothermic.</em>

Hope this helps, have a good day. c;


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One mole of nitrogen and one mole of neon are combined in a closed container at STP.How big is the container?V = __________ L
cestrela7 [59]

Answer : The volume of container will be 44.8 L

Explanation :

At STP condition,  

The temperature and pressure are 273 K and 1 atm respectively.

As we know that at STP, 1 mole of substance occupies 22.4 L volume of gas.

As per question,

1 mole of nitrogen gas occupies 22.4 L volume

and,

1 mole of neon gas also occupies 22.4 L volume

Thus, total volume will be:

Total volume of container = 22.4 + 22.4 = 44.8 L

Hence, the volume of container will be 44.8 L

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3 years ago
How many moles of H2 can be made from complete reaction of 3.0 moles of Al?
tresset_1 [31]

Answer: 4.5 moles of H_{2} can be made from complete reaction of 3.0 moles of Al.

Explanation:

The given reaction equation is as follows.

2Al + 6HCl \rightarrow 2AlCl_{3} + 3H_{2}

This shows that 2 moles of Al reacts with 6 moles of HCl. So, the amount of HCl required to react with 1 mole Al is three times the amount of HCl.

Therefore, 3 moles of Al will react with 9 moles of HCl to give 3 moles of AlCl_{3} and \frac{9}{2} moles of H_{2}.

The reaction equation now will be as follows.

3Al + 9HCl \rightarrow 3AlCl_{3} + \frac{9}{2}H_{2}

The moles \frac{9}{2} can also be written as 4.5 moles.

Thus, we can conclude that 4.5 moles of H_{2} can be made from complete reaction of 3.0 moles of Al.

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Electrons spill in shells in the nucleous the closest shell (n=1) can contain the maximum of. Electrons
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Answer is: volume will be 6,7 L.
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p</span>₁V₁ = p₂V₂.
90 kPa · 5 L = 67 kPa · V₂.
V₂ = 90 kPa · 5 L / 67 kPa.
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