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3 years ago

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For an exothermic reaction at equilibrium, how will increasing the temperature affect Keq?

1 answer:

Sonja [21]3 years ago

8 0

Question:

<em>For an exothermic reaction at equilibrium, how will increasing the temperature affect Keq?</em>

Answer:

<em>The reaction will proceed towards the liquid phase. Heat is on the reactant side of the equation. Lowering temperature will shift equilibrium left, creating more liquid water. A reaction that is exothermic releases heat, while an endothermic reaction absorbs heat.</em>

<em>If you increase the temperature, the position of equilibrium will move in such a way as to reduce the temperature again. It will do that by favouring the reaction which absorbs heat. In the equilibrium, that will be the back reaction because the forward reaction is exothermic.</em>

Hope this helps, have a good day. c;

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A 2.00-g sample of a large biomolecule was dissolved in 15.0 g carbon tetrachloride. the boiling point of this solution was dete

Katarina [22]

We will use boiling point formula:

ΔT = i Kb m

when ΔT is the temperature change from the pure solvent's boiling point to the boiling point of the solution = 77.85 °C - 76.5 °C = 1.35

and Kb is the boiling point constant =5.03

and m = molality

i = vant's Hoff factor

so by substitution, we can get the molality:

1.35 = 1 * 5.03 * m

∴ m = 0.27

when molality = moles / mass Kg

0.27 = moles / 0.015Kg

∴ moles = 0.00405 moles

∴ The molar mass = mass / moles
= 2 g / 0.00405 moles
= 493.8 g /mol

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3 years ago

Quincy wants to see a real example of rock weathering. Where would be the best place for him to go? A. up on the roof of his hou

zhannawk [14.2K]

Answer:

Option (D)

Explanation:

Weathering is usually defined as the disintegration of rocks at the surface of the earth. This break down of rocks is mainly caused by the geological processes that occur on the earth's surface. This process results in the formation of sediments that are transported and deposited in a new environment.

This weathering process primarily takes place in three different ways such as-

Physical weathering- Here, the rocks are broken down by the physical agents such as wind, water, ice.

Chemical weathering- Here the rocks are broken down when interacts with the chemical containing water.

Biological weathering- here, the rocks are broken down due to the activities done by organisms such as plants and animals.

In the given condition, Quincy can see a real example of rock weathering in the high mountainous region, as in the mountainous region the rocks are frequently weathered and eroded by the agents such as wind, water, and ice.

Thus, the correct answer is option (D).

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3 years ago

3) In the Hydrolysis of Disaccharides and Polysaccharides portion of the lab, starch should give one positive iodine test and on

AfilCa [17]

Answer: potassium iodide is the basic test for starch,and the positive test is blue-black coloration, any other test substance which is not starch will give a negative results.

Explanation:

Starch is an example of polysaccharide and since the standard test for it is potassium iodide solution, it gives a positive test.

Diasaccharides e.g maltose are reducing sugars.their standard test is BENEDICT test .

Therefore, in the hydrolysis; starch should give a positve test, while Diasaccharides should give negative rest.

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3 years ago

8.3 miles of sodium chloride in 0.65 of water.

Allisa [31]

Answer:

12.77 M

Explanation:

8.3 moles of NaCl in .65 L of water ? Looking for M ?

8.3 M / .65 L = 12.77 M

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2 years ago

Indicate the changes (increases, decreases, does not change) in its volume when the pressure undergoes the following changes at

Inga [223]

The question is missing information. Here is the complete question.

A gas at a pressure of 2.0 atm is in a closed container. Indicate the changes (if any) in its volume when the pressure undergoes the following changes at constant temperature and constant amount of gas. Match the words in the left with the column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer.

1. The pressure increases to 6.0 atm. The volume ________

2. The pressure drops to 0.40 atm. The volume _________

3. The pressure remains at 2.0 atm. The volume _________

Answer: 1. Decreases

2. Increases

3. Does not change

Explanation: According to the Ideal Gas Law, <u>Pressure</u>, <u>Volume</u> and <u>Temperature</u> of an ideal gas is related, as the following: PV = nRT.

In this case, since temperature (T) and amount of gas (n) are constant, the <em><u>Boyle's</u></em> <em><u>Law</u></em> can be used.

The law states that the volume of a given gas, under the conditios of temperature and amount of it are constant, is inversely proportional to the applied pressure: P₁.V₁ = P₂.V₂

For case 1.)

Initial P (P₁) = 2

Initial V (V₁) = V

Final P (P₂) = 6

P₁.V₁ = P₂.V₂

2.V = 6.V₂

V₂ = 1/3V

When the pressure increases to 6 atm, volume <em><u>decreases</u></em> by 1/3.

For case 2.)

P₁ = 2

V₁ = V

P₂ = 0.4

2.V = 0.4V₂

V₂ = 5V

When pressure drops to 0.4 atm, volume <em><u>increases</u></em> by 5.

For case 3.)

Since there are no change in the pressure, the volume is the same from the beginning, so <em><u>does not change</u></em>.

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3 years ago