In the operation of the Heat Transfer Service Unit, one of the variables you can control is the rate of cooling water flowing ag
ainst the cold side of the metal under study. If the temperature of the hot side of the metal is kept constant, what would be the expected effect of an increase in the rate of flow of cooling water against the cold side? 0 A. The rate of heat transfer through the material would increase. O B. The temperature gradient across the specimen would decrease. ° C. The rate of heat transfer through the material would decrease. ° C. The temperature at the hot side would increase.
A. The rate of heat transfer through the material would increase.
Explanation:
Remember that when doing heat transfer problems you will always have a hotter side than the other, and that is the one that you´d like to cool off, ig you increase the rate of flow of cooling water agains the cold side you will be having more cold fluid flowing thru that pipe, meaning that you can transfer more heat to that side of the heat transfer. So the answer would be A. The rate of heat transfer through the material would increase.
A. The rate of heat transfer through the material would increase.
Explanation:
To calculate the heat transfer in a heat exchanger you decide that there is not heat leakage to the surroundings, that means that magnitude of the two transfer rates will be equal. Any heat lost by the hot fluid, is gained by the cold fluid. The equation that describes this is Q = m×Cp×dT
Where:
heat = mass flow ×specific heat capacity × temperature difference
So if we increase the rate of flow of cooling water and the other variables that ypu can control remain the same, the result is that the rate of heat transfer through the material would increase, as it is stated in option a.
<span>The type of bond that a
Phosphorous pentachloride have is an Ionic Bonding. It is a form of chemical
bond that encompasses the electrostatic attraction between oppositely charged
ions which serves as the primary interaction happening in ionic compound. Phosphorus
has 5 valence electrons and Chlorine has 7 valence electrons. Phosphorus contributes
1 electron to each chlorine and all the 6 achieve 8 electrons in the outer
shell thus creating an ionic bond.</span>
During MITOSIS, the parent, diploid (2n), cell is divided to create two identical, diploid (2n), daughter cells. ... After cytokinesis, the ploidy of the daughter cells remains the same because each daughter cell contains 4 chromatids, as the parent cell did.
