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asambeis [7]
3 years ago
9

What is the answer and how should the problem look?y-12 = -22

Mathematics
2 answers:
Alexus [3.1K]3 years ago
4 0
Y-12= -22
 +12  +12
________
y= -10

The answer to this problem is y= -10. Hope this helps. (。・艸-。)-☆
Alchen [17]3 years ago
3 0
If solving for y

remember, you can do anything to an equation as long as you do it to both sides
y-12=-22
add 12 to both sides
y+12-12=12-22
y+0=-10
y=-10
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Step-by-step explanation:

3 0
3 years ago
How do I set up an equation
tiny-mole [99]

the equation here would be set up by doing

44.4 - 10.9 = 33.5

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6 0
3 years ago
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Solve for the unknown variable 2/5(3x-4)=-4
Elanso [62]

Answer:

x = -2

Step-by-step explanation:

Solve for x:

(2 (3 x - 4))/5 = -4

Multiply both sides of (2 (3 x - 4))/5 = -4 by 5/2:

(5×2 (3 x - 4))/(2×5) = -4×5/2

5/2×2/5 = (5×2)/(2×5):

(5×2)/(2×5) (3 x - 4) = -4×5/2

5/2 (-4) = (5 (-4))/2:

(5×2 (3 x - 4))/(2×5) = (-4×5)/2

(5×2 (3 x - 4))/(2×5) = (2×5)/(2×5)×(3 x - 4) = 3 x - 4:

3 x - 4 = (-4×5)/2

(-4)/2 = (2 (-2))/2 = -2:

3 x - 4 = 5×-2

5 (-2) = -10:

3 x - 4 = -10

Add 4 to both sides:

3 x + (4 - 4) = 4 - 10

4 - 4 = 0:

3 x = 4 - 10

4 - 10 = -6:

3 x = -6

Divide both sides of 3 x = -6 by 3:

(3 x)/3 = (-6)/3

3/3 = 1:

x = (-6)/3

The gcd of -6 and 3 is 3, so (-6)/3 = (3 (-2))/(3×1) = 3/3×-2 = -2:

Answer:  x = -2

6 0
3 years ago
Read 2 more answers
If
baherus [9]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: cos 330 = \frac{\sqrt3}{2}

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}

Proof LHS → RHS:

LHS                          cos 165

Double-Angle:        cos (2 · 165) = 2 cos² 165 - 1

                             ⇒ cos 330 = 2 cos² 165 - 1

                             ⇒ 2 cos² 165  = cos 330 + 1

Given:                        2 \cos^2 165  = \dfrac{\sqrt3}{2} + 1

                              \rightarrow 2 \cos^2 165  = \dfrac{\sqrt3}{2} + \dfrac{2}{2}

Divide by 2:               \cos^2 165  = \dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}

                             \rightarrow \cos^2 165  = \dfrac{2\sqrt3+4}{8}

Square root:             \sqrt{\cos^2 165}  = \sqrt{\dfrac{4+2\sqrt3}{8}}

Scratchwork:            \cos^2 165  = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2

                             \rightarrow \cos 165  = \pm \dfrac{\sqrt3+1}{2\sqrt2}

             Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

                             \rightarrow \cos 165  = - \dfrac{\sqrt3+1}{2\sqrt2}

LHS = RHS \checkmark

4 0
4 years ago
How do you solve x^2+11x+18=0 with either quadratic formula. factoring. or squarerooting
Lostsunrise [7]
I always prefer factoring, if there are simple factors.
There are simple factors here.

x² + 11x + 18 = 0

(x + 2) (x + 9) = 0

The left side is zero if either factor is zero.

First factor:
x + 2 = 0
<u>x = -2</u>

Second factor:
x + 9 = 0
<u>x = -9 </u>

 
3 0
3 years ago
Read 2 more answers
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