All categories

3 years ago

What is the answer and how should the problem look?y-12 = -22

Mathematics

2 answers:

Alexus [3.1K]3 years ago

4 0

Y-12= -22
+12 +12
________
y= -10

The answer to this problem is y= -10. Hope this helps. (。・艸-。)-☆

Alchen [17]3 years ago

3 0

If solving for y

remember, you can do anything to an equation as long as you do it to both sides
y-12=-22
add 12 to both sides
y+12-12=12-22
y+0=-10
y=-10

You might be interested in

Please help me!!!!!!!!!!!

yanalaym [24]

Answer:

yea dude thats a whole project you cant just put it on brainly and expect us to do it for you. stop being lazy and abusing the website

Step-by-step explanation:

3 0

3 years ago

How do I set up an equation

tiny-mole [99]

the equation here would be set up by doing

44.4 - 10.9 = 33.5

Carlsbad caverns is 33.5 kilometers long.

6 0

3 years ago

Read 2 more answers

Solve for the unknown variable 2/5(3x-4)=-4

Elanso [62]

Answer:

x = -2

Step-by-step explanation:

Solve for x:

(2 (3 x - 4))/5 = -4

Multiply both sides of (2 (3 x - 4))/5 = -4 by 5/2:

(5×2 (3 x - 4))/(2×5) = -4×5/2

5/2×2/5 = (5×2)/(2×5):

(5×2)/(2×5) (3 x - 4) = -4×5/2

5/2 (-4) = (5 (-4))/2:

(5×2 (3 x - 4))/(2×5) = (-4×5)/2

(5×2 (3 x - 4))/(2×5) = (2×5)/(2×5)×(3 x - 4) = 3 x - 4:

3 x - 4 = (-4×5)/2

(-4)/2 = (2 (-2))/2 = -2:

3 x - 4 = 5×-2

5 (-2) = -10:

3 x - 4 = -10

Add 4 to both sides:

3 x + (4 - 4) = 4 - 10

4 - 4 = 0:

3 x = 4 - 10

4 - 10 = -6:

3 x = -6

Divide both sides of 3 x = -6 by 3:

(3 x)/3 = (-6)/3

3/3 = 1:

x = (-6)/3

The gcd of -6 and 3 is 3, so (-6)/3 = (3 (-2))/(3×1) = 3/3×-2 = -2:

Answer: x = -2

6 0

3 years ago

Read 2 more answers

baherus [9]

Answer: see proof below

Step-by-step explanation:

Given: cos 330 = $\frac{\sqrt3}{2}$

Use the Double-Angle Identity: cos 2A = 2 cos² A - 1

$\text{Scratchwork:}\quad \bigg(\dfrac{\sqrt3 + 2}{2\sqrt2}\bigg)^2 = \dfrac{2\sqrt3 + 4}{8}$

Proof LHS → RHS:

LHS cos 165

Double-Angle: cos (2 · 165) = 2 cos² 165 - 1

⇒ cos 330 = 2 cos² 165 - 1

⇒ 2 cos² 165 = cos 330 + 1

Given: $2 \cos^2 165 = \dfrac{\sqrt3}{2} + 1$

$\rightarrow 2 \cos^2 165 = \dfrac{\sqrt3}{2} + \dfrac{2}{2}$

Divide by 2: $\cos^2 165 = \dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \bigg(\dfrac{2}{2}\bigg)\dfrac{\sqrt3+2}{4}$

$\rightarrow \cos^2 165 = \dfrac{2\sqrt3+4}{8}$

Square root: $\sqrt{\cos^2 165} = \sqrt{\dfrac{4+2\sqrt3}{8}}$

Scratchwork: $\cos^2 165 = \bigg(\dfrac{\sqrt3+1}{2\sqrt2}\bigg)^2$

$\rightarrow \cos 165 = \pm \dfrac{\sqrt3+1}{2\sqrt2}$

Since cos 165 is in the 2nd Quadrant, the sign is NEGATIVE

$\rightarrow \cos 165 = - \dfrac{\sqrt3+1}{2\sqrt2}$

LHS = RHS $\checkmark$

4 0

4 years ago

How do you solve x^2+11x+18=0 with either quadratic formula. factoring. or squarerooting

Lostsunrise [7]

I always prefer factoring, if there are simple factors.
There are simple factors here.

x² + 11x + 18 = 0

(x + 2) (x + 9) = 0

The left side is zero if either factor is zero.

First factor:
x + 2 = 0
x = -2

Second factor:
x + 9 = 0
x = -9 

3 0

3 years ago

Read 2 more answers