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jonny [76]
3 years ago
5

Why is the ability to respond to stimuli critical?

Chemistry
2 answers:
shtirl [24]3 years ago
5 0
1. Because that shows that you're a living thing because all living things can respond to stimuli.
2. Because an example of stimuli is a virus. If you couldn't respond to it (by fighting against it) you would probably die.

Hope it helps

wolverine [178]3 years ago
3 0

Answer & explanation:

The stimuli are captured by the sensory system receptors through electrical impulses, being translated by the central nervous system (CNS) into sensations and generating responses.

Thanks to the stimuli, we can react to the cold or heat on our skin, see the things and colors around us, taste and smell foods and hear and interpret sounds.

The sensory system, responding to stimuli, maintains the functioning of the five senses, in addition to controlling the immune system, the organs and the functioning of the other systems of our body.

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What reagent is <br>used to test for starch<br>​
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Answer:

iodine

Explanation:

In the presence of starch, iodine turns a blue/black colour. It is possible to distinguish starch from glucose (and other carbohydrates) using this iodine solution test. For example, if iodine is added to a peeled potato then it will turn black. Benedict's reagent can be used to test for glucose.

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3 years ago
Lipids (also known as fats) have two types of monomers called
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2 years ago
Select the example of symbiosis, chosen from the list below that is best described by the statement shown.
ololo11 [35]

Answer:

can you show us the list

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8 0
2 years ago
2AgNO3 + CaCl2 → 2AgCl + Ca(NO3)2
Harrizon [31]

It can be found that 337.5 g of AgCl formed from 100 g of silver nitrate and 258.4 g of AgCl from 100 g of CaCl₂.

<u>Explanation:</u>

2AgNO₃ + CaCl₂ → 2 AgCl + Ca(NO₃)₂

We have to find the amount of AgCl formed from 100 g of Silver nitrate by writing the expression.

100 g \text { of } A g N O_{3} \times \frac{2 \text { mol } A g N O_{3}}{169.87 g A g N O_{3}} \times \frac{2 \text { mol } A g C l}{1 \text { mol } A g N O_{3}} \times \frac{143.32 g A g C l}{1 \text { mol } A g C l}

= 337.5 g AgCl

In the same way, we can find the amount of silver chloride produced from 100 g of Calcium chloride.

It can be found as 258.4 g of AgCl produced from 100 g of Calcium chloride.

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3 years ago
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stiks02 [169]

Answer:

4 weeks

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