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BlackZzzverrR [31]
3 years ago
10

Which type of intermolecular attractive force operates between (part A) all molecules, (part B) polar molecules, (part C) the hy

drogen atom of a polar bond and a nearby small electronegative atom
Chemistry
1 answer:
nydimaria [60]3 years ago
3 0

Answer:

PART A: The LDF occurs between all molecules. Dispersion forces result from shifting electron clouds, which cause weak, temporary dipole.

PART B: Dipole dipole operates only between polar molecules. This is when two polar molecules get near each other and the positively charged portion of the molecule is attracted to the negatively charged portion of another molecule.

PART C: Dipole dipole and in some cases hydrogen bonding operate between the hydrogen atom of a polar bond and a nearby small electronegative atom. Only if the atom bonded to it were F, O or N it would be hydrogen bonding. Otherwise it is dipole dipole.

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Predict the ground-state electron configuration of the following ions. Write your answers in abbreviated form, that is, beginnin
abruzzese [7]

These are three questions and three complete answers

Answer:

a) Cr²⁺: [Ar] 4s² 3d²

b) Cu²⁺: [Ar] 4s² 3d⁷

c) Co³⁺: [Ar] 4s² 3d⁴

Explanation:

<u>a) Cr²⁺</u>

  • Z = 24
  • Number of protons: 24
  • Number of elecrons of the neutral atom: 24
  • Charge of the ions: + 2
  • Number of electrons of the ion: 24 - charge = 24 - 2 = 22.
  • Electron configuration:

       Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....

       Hence, for 22 electrons you get:

       1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d²

  • Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:

       

        [Ar] 4s² 3d²

<u>b) Cu²⁺</u>

  • Z = 29
  • Number of protons: 29
  • Number of elecrons of the neutral atom: 29
  • Charge of the ion: + 2
  • Number of electrons of the ion: 29 - charge = 29 - 2 = 27.
  • Electron configuration:

       Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....

       Hence, for 27 electrons you get:

       1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁷

  • Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:

       

        [Ar] 4s² 3d⁷

<u>c) Co³⁺</u>

  • Z = 27
  • Number of protons: 27
  • Number of elecrons of the neutral atom: 27
  • Charge of the ion: + 3
  • Number of electrons of the ion: 27 - charge = 27 - 3 = 24.
  • Electron configuration:

       Fill the orbitals in increasing order of energy. Using Aufbau's rules the order is: 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁶ .....

       Hence, for 24 electrons you get:

       1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁴

  • Abbreviated notation: since the last complete level is the number 3s² 3p⁶, you use the noble gas of the period 3, which is Ar, and the configuration is:

       

        [Ar] 4s² 3d⁴

6 0
3 years ago
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