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3 years ago

Which of these equations is balanced? a. 3 H2SO4 + 2Al → Al2(SO4)3 + 3H2 b. 2KCl + Pb(NO3)2 → KNO3 + PbCl2 a b a and b neither

2 answers:

8 0

A.) 3 H2SO4 + 2 Al > Al2(SO4)3 + 3 H2
6 H+ +3 S +12 O +2 Al> 2 Al + 3S + 12O + 6H+
This one is balanced, with 6 H, 3 S, 12 O, and 2 Al on both sides.
B.) 2KCl + Pb(NO3)2 > KNO3 + PbCl2
2K + 2Cl + Pb + 2N +6 O > 1 K + 1 N+ 3 O + Pb + 2 Cl
This one is not balanced as there is 2 K, 6 O and 2 N on the reactants side but only 1 K, 3 O, and 1 N on the products side.
Therefore, only A.) is balanced

Nataly_w [17]3 years ago

3 0

Only equation A is balanced.
To balance equation B, simply add another molecule of KNO3, so the final equation would be:
2KCl + Pb(NO3)2 ---> 2KNO3 + PbCl2

Please mark my answer as brainliest

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Complete the following single replacement reaction. If they don’t react, just write “NR”

Kipish [7]

Here we have to complete the given single replacement reactions.

The replacement reactions are-

1) Fe (s) + CuCl₂ (aq) → FeCl₂ (aq) + Cu (s)

2) Cu (s) + FeCl₂ (aq) → NA

3) K (s) + NiBr₂ (aq) → NA

4) Ni (s) + KBr (aq) → NiBr₂ (aq) + K (s)

5) Zn (s) + Ca(NO₃)₂ (aq) → Zn(NO₃)₂ (aq) + Ca (s)

6) Ca (s) + Zn(NO₃)₂ (aq) → NA

The replacement reactions can be explained in light of the redox potential.

The standard reduction potential of the half cells involved in these reactions are:

Fe²⁺ + 2e → Fe (E° = -0.441V); Cu²⁺ + 2e → Cu (E° = 0.674V)

Ni²⁺ + 2e → Ni (E° = -0.23V); Zn²⁺ + 2e → Zn (E° = -0.763V)

We know the half cell reactions in which the standard reduction potentials are positive are allowed.

1) The reaction is possible as Cu²⁺/Cu and Fe/Fe²⁺ standard reduction potentials are positive.

2) The reaction is not possible as Cu/Cu²⁺ and Fe²⁺/Fe standard reduction potentials are negative.

3) The reaction is not possible as Ni²⁺/Ni standard reduction potential is negative.

4) The reaction is possible as Ni/Ni²⁺ standard reduction potential is positive.

5) The reaction is possible as Zn/Zn²⁺ standard reduction potential is positive.

6) The reaction is possible as Zn²⁺/Zn standard reduction potential is negative.

4 0

2 years ago

The molecular weight of a gas that has a density of 5.75 g/l at stp is __________ g/mol.

Ira Lisetskai [31]

Answer : The molecular weight of a gas is, 128.9 g/mole

Explanation : Given,

Density of a gas = 5.75 g/L

First we have to calculate the moles of gas.

At STP,

As, 22.4 liter volume of gas present in 1 mole of gas

So, 1 liter volume of gas present in $\frac{1}{22.4}=0.0446$ mole of gas

Now we have to calculate the molecular weight of a gas.

Formula used :

$\text{Moles of gas}=\frac{\text{Mass of a gas}}{\text{Molecular weight of a gas}}$

Now put all the given values in this formula, we get the molecular weight of a gas.

$0.0446mole=\frac{5.75g}{\text{Molecular weight of a gas}}$

$\text{Molecular weight of a gas}=128.9g/mole$

Therefore, the molecular weight of a gas is, 128.9 g/mole

8 0

3 years ago

Read 2 more answers

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

3 years ago

The formula equation of Acetylene + oxygen ----> carbon dioxide + water

snow_lady [41]

Answer:

The final balanced equation is : 2C2H2+5O2→4CO2+2H2O.

8 0

2 years ago

Design a synthesis of 2-bromo-1-chloro-4-nitrobenzene from benzene or any mono-substituted benzene. Part 1 out of 6 choose the b

Oxana [17]

2-bromo-1-chloro-4-nitrobenzene is being synthesized in following sequence:

Step 1: Chlorination of Benzene:

This is Halogenation reaction of benzene. In this step benzene is reacted with Chlorine gas in the presence of lewis acid (i.e. FeCl₃). This results in the formation of Chlorobenzene as shown in red step below.

Step 2: Nitration of Chlorobenzene:

The chlorine atom on benzene has a ortho para directing effect. Therefore, the nitration of chlorobenzene will yield para nitro chlorobenzene as shown in blue step below.

Step 3: Bromination of 1-chloro-4-nitrobenzene:

In this step bromination is done by reacting bromine in the presence of lewis acid. The chlorine being ortho para directing in nature and nitro group being meta directing in nature will direct the incoming Br⁺ (electrophile) to the desired location. Hence, 2-bromo-1-chloro-4-nitrobenzene is synthesized in good yield.

6 0

2 years ago