When you mix soap with water, you are diluting it unto less strong soap.
When you use soap and water mixed togehter to wash your hands, you are using the chemical propertiies of the soap to your advantage. The soap is made of hundreds of thousands of tiny strands that have a "water loving" end and a "oil loving" end. The oil loving ends attach to the oil on your skin, and the water loving ends stick out. This is called a micelle. Thousnds of micelles form and are ready to be rinsed away, with the oil that was on your skin inside of them. We need soap insted of just water because oil does not mix with water, and therfore cannot just be rinsed off with it.
<h2>Mark brainliest?</h2>
Answer:
I'm the best bro in the league do you want to play sc
Explanation:
a) They are solid at ambient temperatures of 25 ° C and pressure of 1 atm.
b) Ionic compounds represent high temperature melting and boiling.
c) They are hard and brittle and then subjected to the impact, break easily, creating planar faces.
d) When dissolved in water, or pure liquid, carry electrical current due to the existence of ions that move freely and can be attracted by the electrodes, closing the electric circuit.
<span>e) His solvent is water. </span>
The answer is B
Explanation:The core of the sun is known as nuclear fusion and involves hydrogen nuclei combining together to form helium.
Answer:
Explanation:
To find the theoretical yield of the equation. First identify the limiting reactant in a chemical equation.
Step 1: write out the equation and balance it.
Al+ 3mno2=3mn+ 2Alo3.
The limiting reactant is mn02 because it is not found in excess.
Step 2: convert the % to gram . All contain 67.2% mole and mno2 will be 100-67.2= 32.8
All=67.2÷100×290(total gram of the reactants)=194.88g
Mno2=32.8÷100×290g=94.12g.
Step 3:calculate the molar mass of mno2 and that of mn. The atomic mass of mn is 54.9380 and that of oxygen is 16.
Mno2=54.938+ (16)2=86.98g/mol.
Mn=54.938.
Step 4:
From your balanced equation , calculate mn.
94.12g mno2× (1mol mno2÷86.98(molarmass) of mno2×3 mol of mn/4molAl×54.938g of mn÷1mol of mn.
94.12g×1÷86.98g×3÷4×54.938÷1
=44.58g
