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NNADVOKAT [17]
3 years ago
11

If a liquid dissolves in a gas, in what state will the solution be? Explain your answer.

Chemistry
1 answer:
disa [49]3 years ago
5 0
It would be solid because you said it dissolves...Hope this helped :)
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What is the relationship between the concentration and the rate of the reaction?
zalisa [80]

Answer:

When the concentration of all the reactants increases, more molecules or ions interact to form new compounds, and the rate of reaction increases. When the concentration of a reactant decreases, there are fewer of that molecule or ion present, and the rate of reaction decreases.

3 0
3 years ago
2. A 90 g bag of trail mix is contains 22% nuts, 35% granola, 18% dried fruit. The rest is chocolate chips.
elena-14-01-66 [18.8K]
There are:

19.8g of nuts (90x0.22=19.8)
31.5g of granola (90x0.35=31.5)
16.2g of dried fruit (90x0.18=16.2)
22.5g of chocolate chips (90x0.25=22.5)
4 0
3 years ago
The complete combustion of octane, C8H18, the main component of gasoline, proceeds as follows: 2C8H18 (l) 25 O2(g) --> 16 CO2
Svet_ta [14]
The ratio of mole number of the reactants and products is equal to the coefficients. So the answer is a. 18.75 mol. b. 35.1 g. c. 1.38 * 10^5 g.
7 0
3 years ago
Read 2 more answers
What is the volume of 3.00 mole of ideal gas at 100.0 C and 2.00 kPa
Novosadov [1.4K]

Answer:

The volume for the ideal gas is: 4647.5 Liters

Explanation:

Formula for the Ideal Gases Law must be applied to solve this question:

P . V = n .  R . T

We convert the T° to K → 100°C + 273 = 373 K

We convert pressure value from kPa to atm.

2 kPa . 1atm/101.3 kPa = 0.0197 atm

We replace data in the formula.

V = ( n . R . T) / P → (3 mol . 0.082 . 373K) / 0.0197 atm =

The volume for the ideal gas is: 4647.5 Liters

8 0
3 years ago
303 K into °C <br>How To convert 303 K into °C​
irga5000 [103]

Answer:

29.85°C

Explanation:

0°K is absolute zero.  That is is same as -273.15°C.

To find C, subtract 273.15 from the temperature in °K.

303K - 273.15°C = <em><u>29.85°C</u></em>

5 0
2 years ago
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