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NNADVOKAT [17]
3 years ago
11

If a liquid dissolves in a gas, in what state will the solution be? Explain your answer.

Chemistry
1 answer:
disa [49]3 years ago
5 0
It would be solid because you said it dissolves...Hope this helped :)
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If it takes 20757 J to heat 96.5 g of a substance from 18.76°C to 78.62 °C, what is the specific heat of the substance?
Free_Kalibri [48]

http://www.its.org/content/watch-kansas-city-chiefs-vs-cleveland-browns-live-stream-free-nfl

5 0
3 years ago
If 0.094 moles of magnesium react with excess oxygen, how many moles of magnesium oxide would be formed?
VMariaS [17]

The equation for this reaction is

\text{Mg}+\text{O} \longrightarrow \text{MgO}

This means that for every mole of magnesium consumed, 1 mole of magnesium oxide is produced.

So, the answer is <u>0.094</u> moles.

6 0
2 years ago
Suppose a layer of oil is on the top of a beaker of water. Water in many oils is slightly soluble, so its concentration is so lo
rodikova [14]

Explanation:

It is given that energy to transfer one water molecule is 2.208 \times 10^{-20} J/molecule

As it is known that in 1 mole there are 6.022 \times 10^{23} atoms.

So, energy in 1 mole = 2.208 \times 10^{-20} \times 6.022 \times 10^{23} J/mol

                                  = 13.3 kJ/mol

As,    log \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 \times 8.314 atm L/mol K} \times \frac{T_{2} - T_{1}}{T_{1}T_{2}}

Putting the given values in the above formula as follows.

                log \frac{k_{2}}{k_{1}} = \frac{E_{a}}{2.303 \times 8.314 atm L/mol K} \times \frac{T_{2} - T_{1}}{T_{1}T_{2}}

               log \frac{k_{2}}{k_{1}} = \frac{13.3 kJ/mol}{2.303 \times 8.314 atm L/mol K} \times \frac{293 K - 283 K}{283K \times 293 K}

                  log \frac{k_{2}}{k_{1}} = 0.08377

                       \frac{k_{2}}{k_{1}} = 1.213 = \frac{Concentration_{2}}{Concentration_{1}}

                 Concentration_{2} = 1.213 \times Concentration_{1}

                                             = 1.213 \times 9 \times 10^{-4}

                                             = 10.915 \times 10^{-4} water molecules per oil molecule

Thus, we can conclude that the equilibrium concentration at 293 K, assuming that nothing else changes is 10.915 \times 10^{-4}.

             

4 0
3 years ago
What was the molecular geometry for SC16?
nikdorinn [45]

Answer:

I'm assuming this is for the SCl₆ compound and not SC₁₆? If so, the molecular geometry is octahedral.

Explanation:

There are 6 regions and zero lone pairs surrounding the central atom (S).

3 0
2 years ago
What is the mass of a proton equal to
ExtremeBDS [4]
The mass of a proton = 1.6726219 × 10^-27 kg.

It’s almost the exact same number as the mass of a neutron, which is 1.674927471×10^-27 kg. The mass of an electon is much less, even negligible.

I hope this helped you out!
6 0
3 years ago
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