Answer:
bruh
Explanation:
The purpose of this lab was to explore the different types of chemical reactions in this laboratory procedure. The question for this lab is, how does knowing the reactants and products help me classify a chemical reaction. In this experiment, I made observations of the reactants and the products. I used these observations to write the balanced chemical equations and to classify the reaction it made.
Answer:
Gas giants.
Explanation:
Jupiter, Saturn, Uranus, and Neptune are the gas giants of our solar system.
1. 2.408 x 10²⁴ molecules
2. 2.408 x 10²⁴ atoms
3. 4.816 x 10²⁴ atoms
<h3>Further explanation</h3>
Given
4 moles of Carbon dioxide.
Required
Carbon dioxide molecules
Carbon atoms
Oxygen atoms?
Solution
1 moles = 6.02 x 10²³ particles(molecules, atoms, ions)
1. Carbon dioxide molecules :
= 4 moles x 6.02 x 10²³
= 2.408 x 10²⁴ molecules
2. The number of Carbon atoms
In CO₂, there is 1 atom C, so the number of atoms :
= 1 x 2.408 x 10²⁴
= 2.408 x 10²⁴ atoms
3. The number of Oxygen atoms :
In CO₂, there is 2 atom O, so the number of atoms :
= 2 x 2.408 x 10²⁴
= 4.816 x 10²⁴ atoms
Answer:
- <u>2.59 × 10⁻⁷ m = 259 nm</u>
Explanation:
You need to calculate the wavelength of a photon with an energy equal to 463 kJ/mol, which is the energy to break an oxygen-hydrogen atom.
The energy of a photon and its wavelength are related by the Planck - Einstein equation:
Where:
- h = Planck constant (6.626 × 10⁻³⁴ J . s) and
- ν = frequency of the photon.
And:
Where:
- c = speed of light (3.00 × 10⁸ m/s in vacuum)
- λ = wavelength of the photon
Thus, you can derive:
Solve for λ:
Before substituting the values, convert the energy, 463 kJ/ mol, to J/bond
- 463 kJ/ mol × 1,000 J/kJ × 1 mol / 6.022 × 10 ²³ atom × 1 bond / atom
= 7.69×10²³ J / bond
Substitute the values and use the energy of one bond:
- λ = 6.626 × 10⁻³⁴ J . s × 3.00 × 10⁸ m/s / 7.69×10²³ J = 2.59 × 10⁻⁷ m
The wavelength of light is usually shown in nanometers:
- 2.59 × 10⁻⁷ m × 10⁹ nm / m = 259 nm ← answer