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Anarel [89]
2 years ago
11

Which statement best describes how matter and energy is cycled through the ecosystem?

Chemistry
1 answer:
sasho [114]2 years ago
3 0

D. Matter and energy are the same.

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A student wants to make 50-mL of a 0.6 mg/L solution of acetic acid. She will be making the solution by diluting a stock with a
IrinaVladis [17]

Answer:

The steps in order are;

1. Obtain a 50-mL volumetric flask

2. Add approximately 10 mL of deionized water to the empty flask

3. Use a pipet to add the appropriate volume of stock solution to the flask

4. Cap the flask and invert several times to mix

5. Fill the volumetric flask with deionized water until the meniscus touches the mark

6. Swirl the flask to mix the contents

The volume of the acetic acid to be added to the solution is 15 mL

Explanation:

The given steps are;

4. Cap the flask and invert several times to mix

5. Fill the volumetric flask with deionized water until the meniscus touches the mark

6. Swirl the flask to mix the contents

1. Obtain a 50-mL volumetric flask

3. Use a pipet to add the appropriate volume of stock solution to the flask

2. Add approximately 10 mL of deionized water to the empty flask

The given parameters are;

The volume of the volumetric flask = 50-mL

The concentration of the final solution of acetic acid = 0.6 mg/L

The concentration of the stock solution = 2.0 mg/L

Let 'x' represent the volume of the stock solution added, we have;

2.0 mg/L·x + (50 - x)×0 = 0.6 mg/L × 50-mL

x = 0.6 mg/L × 50-mL/(2.0 mg/L) = 15 mL

The volume of the stock solution to be added, x = 15 mL

5 0
3 years ago
Balance this chemical equation SiO2+HF=SiF4+H2O
tatuchka [14]

Answer:  SiO2 + 4HF = SiF4 + 2H2O

Explanation:

pls mark brainliest if right if not im so sorry

7 0
3 years ago
Prior to hosting an international soccer match, the local soccer club needs to replace the artifical turf on their field with gr
GuDViN [60]

Answer:

It will cost $68,620.5 to the club to add the grass turf to their field.

Explanation:

length of the field = l = 0.102 km = 0.102 × 1000 m

( 1km = 1000 m)

Width of the field w = 0.069 km = 0.069 × 1000 m

Area of the field , A= l × w

A=0.102\times 1000 m\times 0.069\times 1000 m=7,038 m^2

Cost of grass turfing = 9.75 \$/m^2

Cost of grass turfing on field of 7,038 m^2 :

=7,038 m^2\times 9.75 \$/m^2=\$68,620.5

It will cost $68,620.5 to the club to add the grass turf to their field.

4 0
3 years ago
Is cinnamon ionic or covalent ?
myrzilka [38]

it is covalent because it does not dissolve in water

5 0
3 years ago
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Write a nuclear equation for the beta decay of Promethium-165
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Answer:

see your answer in pic

Explanation:

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