So first you would put these over a common denominator which is 96. You get this by multiplying by 9 and what you do to the denominator you must do to the numerator so you then get 45/96 and 63/96. Pelicans=45/96. Woodpeckers=63/96
Answer:
Yes
We fail to reject the alternative hypothesis Hₐ < 30, that is the average age of students is less than 30
Step-by-step explanation:
Yes because, there is an average age of a sample which can be tested against a null hypotheses
We put
Null hypothesis as H₀ = 30
The alternative hypothesis as Hₐ < 30
We have

With
= 29
μ = 30
σ = 5.2
n = 65
α = 10%
We have
Here we have z = -1.55 and critical z = -1.28
Which gives a critical
of 29.83 with the probability P = 0.061 < 0.1 Hence we reject the null hypothesis as there is sufficient evidence to suggest that the average age is less than 30 years.
Answer:
168 = L + 2W
And you want to maximize LW.
Which means you want to maximize W (168 - 2W), or 168W - 2W^2.
To maximize that, the derivative must go to zero.
0 = 168 - 4W, or W = 42. And L = 84. Done. :-)
Step-by-step explanation: