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Andrei [34K]
3 years ago
10

How do we find the mode of a set of numbers and can there be more than one

Mathematics
1 answer:
AveGali [126]3 years ago
3 0

Answer:There can be more than one mode

Step-by-step explanation

1. The mode is the number that occur more frequently in a given set of numbers.

2. It is true that there can be more than one mode. This is so because more than one number can occur more frequently in a given set of numbers.

For example: In the example below 2 and 3 are the modes.

1, 2, 4, 2, 3, 7, 3

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Let the universal set be the set of integers and let A = {x | x^2 ≤ 5}. Write A using the roster method.
Zarrin [17]

Answer:

Step-by-step explanation:

Given that Z the set of integers is the universal set and

A is given in set builder form.

A = {x | x^2 ≤ 5}

To convert this into roster form, we can find solutions for x

When x^2\leq 5\\|x|\leq \sqrt{5} =2.236

i.e. all integers lying between -2.236 and 2.236

The only integers satisfying this conditions are

-2,-1,0,1,2

Hence A in roster form is

A={-2,-1,0,1,2}

8 0
3 years ago
Is the function f(x) =(4)^x -2 an exponential function. If so, identify the base. If not, why not?
Ne4ueva [31]

Answer:

Yes.

Base: 4

Step-by-step explanation:

Since we have 4 to the power of x, we do indeed have an exponent. The -2 just signifies vertical movement down.

7 0
3 years ago
Which is the value of g(-5) if g(x)=3.4x-8?
irinina [24]
Plug the value -5 in. (3.4)(-5) - 8 is equivalent to -17 - 8. Final answer: g(-5) = -25.
6 0
3 years ago
There are 8 teachers and 4 students how many people are there total?
Elina [12.6K]

Answer:

12 people

Step-by-step explanation:

We have to take to total amount of teachers, which is 8 and add the total amount of students, which there are 4 of. 8+4 is 12, so there are 12 people in total.

5 0
2 years ago
If AB vector =(4 5) and PQ vector=(2p 10) are parallel to each other, find the value of p.​
Sedaia [141]

Answer:

Answer:

They both have q+3/2p, so that means that 2PQ=CB and that means they are parallel to each other

Step-by-step explanation:

PQ=PA+QA

PQ=1/2(2q-p)+2/5*5p=q-1/2p+2p=q+3/2p

CB=2q+3p=2(q+3/2p)

Other explanation: It should be written like this PQ=q+3/2p and CB=2q+3p=2(q+3/2p) they are parallel bcs CB=2*PQ.

8 0
2 years ago
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