So if he drives 50 miles in 1 hour, then he must drive 100 miles in 2 hours. 0.25 is another way of writing 1/4, and to find 1/4 you divide by 4, so 50 ÷ 4 = 12.5 miles. Then you can add this to 100 and get your answer as 112.5 miles.
If you have a calculator, or if you're allowed a calculator, then a simpler way is to just do 2.25 × 50 = 112.5
Hope this helps!
When x=2 y = 110 which means when when x=1 y = 55
the graph would be 11*55 or 605
The table would be 280/4= 70 70*11=770
Which means the difference is 770-605=165
165 is ur answer
Answer:
The acceleration in the system and in the rope is same as 5.88 m/s2.
Step-by-step explanation:
The figure shows two blocks of m1 = 0.8 Kg and m2 = 0.2 kg if the block of mass m2 is dragged by the block of mass m1 calculate the acceleration of the system and the acceleration of the rope
Let the acceleration is a and the tension in the string is T.
Use Newton's second law
![m_1 g - T = m_1 a ..... (1)\\\\T -m_2 g = m_2 a ......(2)\\\\Add both of them \\\\(m_1 - m_2) g = (m_1 + m_2) a \\\\(0.8-0.2)\times9.8 = (0.8+0.2)a\\\\a = 5.88 m/s^2](https://tex.z-dn.net/?f=m_1%20g%20-%20T%20%3D%20m_1%20a%20.....%20%281%29%5C%5C%5C%5CT%20-m_2%20g%20%3D%20m_2%20a%20......%282%29%5C%5C%5C%5CAdd%20both%20of%20them%20%5C%5C%5C%5C%28m_1%20-%20m_2%29%20g%20%3D%20%28m_1%20%2B%20m_2%29%20a%20%5C%5C%5C%5C%280.8-0.2%29%5Ctimes9.8%20%3D%20%280.8%2B0.2%29a%5C%5C%5C%5Ca%20%3D%205.88%20m%2Fs%5E2)
2.75+.003+.158=0
We simplify the equation to the form, which is simple to understand
2.75+.003+.158=0
We move all terms containing to the left and all other terms to the right.
0=0-2.75-0.003-0.158
We simplify left and right side of the equation.
0=-2.911
0=-2.911
The left and right sides are not equal, therefore there is no solution. This equation is invalid.