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3 years ago

Given: -1/2x > 6. Choose the solution set.

1 answer:

4 0

The answer would be B. You multiply the 2 on both sides, getting 12 on the right. Then you divide by -1, and that switches the sign and makes 12 negative.

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Use properties to rewrite the given equation. Which equations have the same solution as 3/5x +2/3 + x = 1/2– 1/5x? Check all tha

vodomira [7]

we have

$\frac{3}{5}x+ \frac{2}{3}+x=\frac{1}{2}-\frac{1}{5}x$

Combine like terms in both sides

$(\frac{3}{5}x+ x)+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

we know that

$(\frac{3}{5}x+ x)=(\frac{3}{5}x+ \frac{5}{5}x)=\frac{8}{5}x$

substitute in the expression above

$\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$ -----> equation A

Multiply equation A by $5*3*2=30$ both sides

$30*(\frac{8}{5}x+\frac{2}{3})=30*(\frac{1}{2}-\frac{1}{5}x)$

$48x+20=15-6x$ ---------> equation B

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$48x+6x=15-20$

$54x=-5$ ---------> equation C

Solve for x

$x=-\frac{5}{54} =-0.09$

We are going to proceed to verify each case to determine the solution.

Case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

the case a) is equal to the equation A

the case a) have the same solution that the given equation

Case b) $18x+20+30x=15-6x$

Combine like terms in left side

$(18x+30x)+20=15-6x$

$(48x)+20=15-6x$

the case b) is equal to the equation B

the case b) have the same solution that the given equation

Case c) $18x+20+x=15-6x$

Combine like terms in left side

$(18x+x)+20=15-6x$

$(19x)+20=15-6x$

$19x+6x=15-20\\25x=-5\\x=-0.20$

$-0.20\neq -0.09$

therefore

the case c) not have the same solution that the given equation

Case d) $24x+30x=-5$

Combine like terms in left side

$54x=-5$

the case d) is equal to the equation C

the case d) have the same solution that the given equation

Case e) $12x+30x=-5$

Combine like terms in left side

$42x=-5$

$x=-5/42=-0.12$

$-0.12\neq -0.09$

therefore

the case e) not have the same solution that the given equation

therefore

the answer is

case a) $\frac{8}{5}x+\frac{2}{3}=\frac{1}{2}-\frac{1}{5}x$

case b) $18x+20+30x=15-6x$

case d) $24x+30x=-5$

7 0

4 years ago

Read 2 more answers

Una empresa fabrica dos modelos de DVD: el modelo A y el modelo B. Se dispone de 50 kilogramos de caucho y de 80 horas de mano d

alexandr1967 [171]

Answer:

¿Cuántos DVD de cada tipo debe fabricar y vender para que la utilidad sea máxima?

Se debe fabricar y vender 20 DVD del modelo A y 30 DVD del modelo B. La utilidad máxima es de de S/. 1 800

Step-by-step explanation:

x : Número de DVD del modelo A

y : Número de DVD del modelo B.

MODELO A MODELO B TOTAL

Cantidad de caucho 1x 1x 50 kg.

Horas de mano de obra 1x 2x 80 horas

U : Utilidad mensual.

La función objetivo, que se debe maximizar, es:

U=30 + 40y

x+ y $\leq 50\\$

x + 2y $\leq 80$

x $\geq 0$

y $\geq 0$

Las coordenadas de los vértices de la región factibles son:

A (0, 0) B (50, 0) C (20, 30) D(0, 40)

Entonces, se evalúa la función objetivo en cada punto:

U (0, 0) = 30 (0) + 40 (0) = 0

U (50, 0) = 30 (50) + 40(0) = 1500

U (90, 0) = 30 (20) + 40 (30) = 1800

U (0, 40) = 30 (0) + 40 (40) =1600

Por consiguiente U tiene un valor máximo en C , en donde: x =20 , y = 30 .

Se debe fabricar y vender 20 DVD del modelo A y 30 DVD del modelo B. La utilidad máxima es de de S/. 1 800.

 30 x  40 y

s.a.



 x  0 (3)

 y  0 (4)

3 0

3 years ago

Cocoa plant type 1 yielded 155 bushels per acre last year at a research farm. This year,

ankoles [38]

Answer:confounding variable

Step-by-step explanation:

7 0

3 years ago

What is the area of the circle in terms of pi? diameter of 4.1m

Black_prince [1.1K]

13.20254313. Pi(2.05)^2. 4.1÷2(for the radius)=2.05.Square it and multiply by Pi. a=pi(r)^2

5 0

3 years ago

Find the area of the circle. Round your answer to the nearest hundredth.

Hoochie [10]

Area is 706.858, rounded is 707

6 0

3 years ago

Read 2 more answers