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Stels [109]
3 years ago
14

The engine power of a car engine is rated 600 hp at 2600 rpm. What is the torque provided by the engine?

Physics
1 answer:
attashe74 [19]3 years ago
5 0

Answer:

1212 N

Explanation:

P  = Power of the car engine = 600 hp

w  = angular speed of rotation in the engine = 2600 rpm

\tau = Torque provided by the engine

Power of the car engine is given as

P = \frac{\tau w}{5252}

Inserting the values

600 = \frac{\tau (2600)}{5252}

\tau = 1212 N

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Joules constant, 4.1868 J/cal, is an equivalence relation for 4.1868 Joules of work for 1 calorie of heat delivered to a substan
Llana [10]

Answer:

The final answer is 6.1 BTU = 6.5621*103 KJ

Explanation:

1 BTU= 252 cal\\1 BTU =252 × 4.2 kJ\\6.1 BTU = 252 × 6.1×4.2 kJ                = 6562.08 kJ\\                = 6.5621 × 103 kJ\\

Hence, 6.1 BTU = 6.5621 × 103 kJ

7 0
3 years ago
Vector A with arrow lies in the xy plane. Both of its components will be negative if it points from the origin into which quadra
Blizzard [7]

Answer:

C

Explanation:

From the question we are told that a vector on the x and y plane face their negative axis

Generally  in the x and y plane thr negative y axis is made to face down opposite the positive y axis

Whilst the negative x axis faces the left which is also alternate to the positive x axis

Generally A vector pointing towards the x and y negative axis fro  the origin (0) will definitely be in the third quadrant

8 0
3 years ago
A radio-controlled car increases its kinetic energy from 4 j to 12 j over a distance of 2 m. what was the average net force on t
just olya [345]
The answer to this is easy once you look at the units for Joules. 1 Joule = 1 N.m (Newton.meter). The 'Newton' is the units of force that we are trying to find, and we know the meters is 2, from the question. So you have an 8Joule or 8N.m energy difference over 2 meters.

well if we know the meters, then the real question is written as:
8N.m = ?N x 2m
so just solve for N;
N = 8N.m / 2m = 4
So F = 4N
3 0
4 years ago
A 12.70 g bullet has a muzzle velocity (at the moment it leaves the end of a firearm) of 430 m/s when rifle with a weight of 25.
Norma-Jean [14]

Answer:

2.1844 m/s

Explanation:

The principle of conservation of momentum can be applied here.

when two objects interact, the total momentum remains the same  provided no external forces are acting.

Consider the whole system , gun and bullet. as an isolated system, so the net momentum is constant. In particular before firing the gun, the net momentum is zero. The conservation of momentum,

0=m_{bullet}*v_{bullet}  + m_{rifle}*v_{rifle}  \\

assume the bullet goes to right side and the gravitational acceleration =10 ms^{-2}

so now the weight of the rifle=\frac{25}{10}  

0=m_{bullet}*v_{bullet}  + m_{rifle}*v_{rifle}  \\\\0=(12.70*10^{-3}) *430ms^{-1} +(\frac{25}{10} )*v_{rifle} \\v_{rifle} =-2.1844ms^{-1}

this is a negative velocity to the right side. that means the rifle recoils to the left side

3 0
3 years ago
There is more role of the moon than the sun to occur tides in oceans?why?
Leya [2.2K]
The ocean tides on earth are caused by both the moon's gravity and the sun's gravity. ... Even though the sun is much more massive and therefore has stronger overall gravity than the moon, the moon is closer to the earth so that its gravitational gradient is stronger than that of the sun.
6 0
3 years ago
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