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irinina [24]
3 years ago
11

Joules constant, 4.1868 J/cal, is an equivalence relation for 4.1868 Joules of work for 1 calorie of heat delivered to a substan

ce. A BTU is a British Thermal Unit (another measure of heat). If 1 BTU=252 cal, how many kilojoules equal 6.1 BTU?Express your answer to 4 significant digits and include the proper unit.
Physics
1 answer:
Llana [10]3 years ago
7 0

Answer:

The final answer is 6.1 BTU = 6.5621*103 KJ

Explanation:

1 BTU= 252 cal\\1 BTU =252 × 4.2 kJ\\6.1 BTU = 252 × 6.1×4.2 kJ                = 6562.08 kJ\\                = 6.5621 × 103 kJ\\

Hence, 6.1 BTU = 6.5621 × 103 kJ

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Liono4ka [1.6K]

Answer:

17.46° W of N

Explanation:

His prow must point westward so that the westward component of his total velocity is equal to the eastward river speed.

3 = 10sinθ

sinθ = 3/10

θ = 17.4576... or about 17.46° W of N

it will take him 5 / 10cos17.46 = 0.52414... hrs. or about 31 min 27 s to cross.

7 0
3 years ago
Does the electrical conductivity of metals have anything to do with the electrostatic chart?
kvv77 [185]
Yes. Electrostatics are known to include the conductivity of metals whenever they start to have electrical flows on them. It's always been there on the list, and one notable instance of it is the flow of electricity in a wire.
3 0
3 years ago
Two 25 kg children are sitting on a merry-go-round that is rotating at 0.10 rad/s. if one child is 1.0 m from the center and the
Grace [21]
The angular speed of the merry-go-round is
ω = 0.10 rad/s

The angular moment of inertia of a mass, m, at a radius, r, from the center of the wheel is
I = mr²

Therefore, the angular moment of inertia for the children are
I₁ = (25 kg)*(1.0 m)² = 25 kg-m²
I₂ = (25 kg)*(1.5 m)² = 56.25 kg-m²

The combined angular momentum is
ω(I₁ + I₂) = (0.10 rad/s)*(25 + 56.25 kg-m²)
               = 8.125 (kg-m²)/s

Answer: 8.125 (kg-m²)/s
8 0
4 years ago
What was the most serious money problem faced by people in the early United States?
alexira [117]
<span>♥B. There was no single medium of exchange.♥
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5 0
3 years ago
A disk between vertebrae in the spine is subjected to a shearing force of 425 N. Find its shear deformation, taking it to have a
zzz [600]

Answer:

option A

Explanation:

given,

shear force = 425 N

Shear modulus = 1.7 × 10⁹ N/m²

disk equivalent to solid cylinder

height = 0.7 cm  and diameter = 6.50 cm

\delta = \dfrac{VL}{AG}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi d^2\times 1.7\times 10^9}\\\\\delta = \dfrac{425\times 0.007}{0.25 \times \pi\times 0.065^2\times 1.7\times 10^9}\\\\\delta  = 5.27 \times 10^{-7} m

hence, the correct answer is option A

3 0
4 years ago
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