Answer:
iv. q/6E0
Step-by-step explanation:
Electric flux formula:
The electic flux formula, of a charge q is given by, through an entire cube, is given by:

In which
is a constant related to the material.
The electric flux through any one face of the cube is:
Key-word is face, and a cube has 6 faces, with the force distributed evenly throughout it. Thus

And the correct answer is given by option iv.
Answer:
Some of the other answers are good examples of solving a system of three equations in three unknowns, which is what this problem is asking. Though the simplest way to solve this problem is actually to notice that, if we sum the three equations, we get:
X + Y = 10
X + Z = 20
+ Y + Z = 24
----------------
2X + 2Y + 2Z = 54
Factoring out the 2, we have 2(X + Y + Z) = 54, and dividing both sides by 2 reveals that X + Y + Z = 27.
Step-by-step explanation:
hopefully this helps
125+42= 167
180-167= 13 degrees
Triangles is always equaled to 180 degrees.
Answer: choice 3
I am pretty sure this is the answer
Since he’s already at -15, if he writes a check for 7 then he’s subtracting more from his account.
So, -15-7=-22
Answer:
$0.025x² . . . where x is a number of percentage points
Step-by-step explanation:
The multiplier for semi-annual compounding will be ...
(1 + x/2)² = 1 + x + x²/4
The multiplier for annual compounding will be ...
1 + x
The multiplier for semiannual compounding is greater by ...
(1 + x + x²/4) - (1 + x) = x²/4
Maria's interest will be greater by $1000×(x²/4) = $250x², where x is a decimal fraction.
If x is a percent value, as in x = 6 when x percent = 6%, then the difference amount is ...
$250·(x/100)² = $0.025x² . . . where x is a number of percentage points
_____
<u>Example</u>:
For x percent = 6%, the difference in interest earned on $1000 for one year is $0.025×6² = $0.90.