Answer:
I think it is 2x-3y=-12 not sure but try it
Sample space={A,R,I,T,H,M,E,T,I,C}
1ST (Choosing T) ==> P(1st draw) = 2/10 = 1/5 = 0.2
2ND (Choosing again a T) ==> P(2nd draw) = 1/9 = 0.11
Since it's a conditional probability then P (1st T AND 2nd T) = 0.2 x 0.11 =0.022
Answers and Step-by-step explanations
13. Square both sides: x^2 + 4x + 4 = 16(x - 2) = 16x - 32
Move all the terms to one side: x^2 - 12x + 36 = 0
Factorize: (x - 6)^2 = 0 ⇒ x = 6
14. Move one of the roots to one side: ![-\sqrt{2x-1} =\sqrt{3x-12}](https://tex.z-dn.net/?f=-%5Csqrt%7B2x-1%7D%20%3D%5Csqrt%7B3x-12%7D)
Square both sides: 2x - 1 = 3x - 12
Solve for x: x = 11
15. Subtract 4 from both sides: x - 4 = ![2\sqrt{x-4}](https://tex.z-dn.net/?f=2%5Csqrt%7Bx-4%7D)
Square both sides: x^2 - 8x + 16 = 4(x - 4) = 4x - 16
Move all the terms to one side: x^2 - 12x + 32 = 0
Factorize: (x - 4)(x - 8) = 0 ⇒ x = 4 or x = 8
16. Square both sides: x^2 - 4x + 4 = 9x - 36
Move all the terms to one side: x^2 - 13x + 40 = 0
Factorize: (x - 5)(x - 8) = 0 ⇒ x = 5 or x = 8
Hope this helps!
Where is it?
step by step:
![\frac{x-7}{x+4} / \frac{x}{x+3} = \frac{x-7}{x+4} * \frac{x+3}{x} = \frac{(x-7)(x+3)}{(x+4)(x)}](https://tex.z-dn.net/?f=%20%20%5Cfrac%7Bx-7%7D%7Bx%2B4%7D%20%2F%20%5Cfrac%7Bx%7D%7Bx%2B3%7D%20%3D%20%20%5Cfrac%7Bx-7%7D%7Bx%2B4%7D%20%2A%20%5Cfrac%7Bx%2B3%7D%7Bx%7D%20%3D%20%20%5Cfrac%7B%28x-7%29%28x%2B3%29%7D%7B%28x%2B4%29%28x%29%7D%20)
Remember that dividing by a fraction is the same as multiplying by the reciprocal (or the reverse) of the fraction on the bottom. A restriction on the domain means that x can not be that value. This occurs when the denominator is zero. If (x+4) = 0 or x = o then the denominator will be zero so the restrictions are x = -4,0. The answer is c.