-3|x+4|+16=7
-3|x+4|=7-16
-3|x+4|=-9
|x+4|=3
x+4=3
x+4=-3
x=-1
x=-7
X1=-7 X2=-1
270 = 27 * 10
= 3*9 * 5*2
= 3 * 3*3 * 5*2
in order from smallest to largest
2*3*3*3 *5
Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) = 
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) = 
P(X=0) = 
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
We know that,
diameter is twice the radius, I.e d = 2r
Now d = 2(8)ft = 16 feet