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3 years ago

Does anyone know the answer ?

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

6 0

Y = 3x - 8
Because y = mx + b, where m is the slope and b is the y-intercept, just substitute the two numbers.

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PLEASE HELP FOR 50 POINTS AND BRAINLIEST Find the unknown measures. Round lengths to the nearest hundredth and angle measures to

Maru [420]

Answer:B

Step-by-step explanation:

4 0

2 years ago

Which of the following statements is true

kolbaska11 [484]

Answer:

D. This quadratic equation two complex solutions.

Step-by-step explanation:

$5x^2 +6x +2= 0\\$

Equating it with

$ax^2 +bx +c= 0\\$

a = 5, b = 6, c = 2

$b^2 -4ac\\= 6^2 - 4\times 5\times 2\\= 36-40\\b^2 -4ac= - 4\\$

$\because b^2 -4ac$ is negative.

Therefore, this quadratic equation two complex solutions.

5 0

3 years ago

The ratio of girls to boys at soccer practice is 3:4. If on Saturday there will be a total of 42 players, how many boys will be

Alex777 [14]

Answer:

$Boys = 24$

$Girls = 18$

Step-by-step explanation:

Given

$G:B= 3:4$

$Total = 42$

Required

Determine the number of boys and girls

We have to convert the ratio to fraction;

Number of girls can be calculated as:

$Girls = \frac{G}{G + B} * Total$

$Girls = \frac{3}{3 + 4} * 42$

$Girls = \frac{3}{7} * 42$

$Girls = 3 * 6$

$Girls = 18$

$Boys = Total - Girls$

$Boys = 42 - 18$

$Boys = 24$

3 0

3 years ago

Can someone please help me out? What's the answer to 4 1/2 plus 3 3/4 ?

Oksanka [162]

Answer:

8 1/4

Step-by-step explanation:

4 1/2 + 3 3/4 make the denominators the same

4 2/4 + 3 3/4 add the whole numbers

7 + 2/4 +3/4 add the fractions

8 1/4

7 0

3 years ago

Read 2 more answers

The matrix A = −14 −6 6 28 12 −4 0 0 4 has characteristic polynomial

rosijanka [135]

Answer:

Characteristic equation:

$p(\lambda) = -\lambda^3 + 2\lambda^2 + 8\lambda$

Eigen values:

$\lambda_1 = 0, \lambda_2 = -2, \lambda_3= 4$

Step-by-step explanation:

We are given the matrix:

$\displaystyle\left[\begin{array}{ccc}-14&-6&6\\28&12&-4\\0&0&4\end{array}\right]$

The characteristic equation can be calculated as:

$det(A-\lambda I) = 0\\|A-\lambda I| = 0$

We follow the following steps to calculate characteristic equation:

$=det\Bigg(\displaystyle\left[\begin{array}{ccc}-14&-6&6\\28&12&-4\\0&0&4\end{array}\right]-\lambda\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]\Bigg)\\\\= det\Bigg(\displaystyle\left[\begin{array}{ccc}-14-\lambda&-6&6\\28&12-\lambda&-4\\0&0&4-\lambda\end{array}\right]\Bigg)\\\\=(-14-\lambda)[(12-\lambda)(4-\lambda)]+6[28(4-\lambda)]-6[(28)(0)-(12-\lambda)(0)]\\\\= -\lambda^3 + 2\lambda^2 + 8\lambda$

$p(\lambda)= -\lambda^3 + 2\lambda^2 + 8\lambda$

To obtain the eigen values, we equate the characteristic equation to 0:

$p(\lambda) = -\lambda^3 + 2\lambda^2 + 8\lambda = 0\\-\lambda(\lambda^2-2\lambda-8) = 0\\-\lambda(\lambda^2-4\lambda+2\lambda-8) = 0\\-\lambda[(\lambda(\lambda-4)+2(\lambda-4)] = 0\\-\lambda(\lambda+2)(\lambda-4) = 0 \\\lambda_1 = 0, \lambda_2 = -2, \lambda_3= 4$

We can arrange the eigen values as:

$\lambda_1 = 0, \lambda_2 = -2, \lambda_3= 4\\-2 < 0 < 4\\\lambda_2 < \lambda_1 < \lambda_3$

3 0

3 years ago