Answer:
26:26
Step-by-step explanation:
I hope I've helped :)
Answer:
$10.50/1.25 = $10.20
Step-by-step explanation:
hope this helps
Given:
Consider the completer question is "If ∆BTS≅∆GHD, BS=25, TS=14, BT=31, GD=4x-11, m∠S=56, m∠B=21 and m∠H=(7y+5), find the values of x and y.
To find:
The values of x and y.
Solution:
We have,
(Given)
(CPCTC)
Divide both sides by 4.
In ∆BTS,
(Angle sum property)
Now,
(CPCTC)
Divide both sides by 7.
Therefore, the value of x is 9 and value of y is 14.
1.5-6-12n. 1-12n
2.-4+40x-35. -39+40x
3.-36x+6+6. 12-36x
4.40n-32+8n. 48n-32
5.7n-28-6. 34-7n
6.-16+20x+3x 23x-16
7. -2n-16+8. -2n-8
8.25b-25-1. 25b-26
9.-4n+15-6n. -10n+15
-1-3x+6. -3x+5
Answer:
a₂ = -3
a₃ = -1
Step-by-step explanation:
We have to insert two arithmetic means between -5 and 1
Let a₁ and b₂ be the two arithmetic means between -5 and 1
-5, a₂, a₃, 1
Here,
We know that the nth term of an Arithmetic sequence
aₙ = a₁ + (n-1)d
a₄ = -5 + (4-1)d
1 = -5 + 3d
1 + 5 = 3d
3d = 6
Dividing both sides by 2
d = 2
Also
a₂ = a₁ + (2-1)d
a₂ = -5 + d
a₂ = -5 + 2 ∵ d = 2
a₂ = -3
a₃ = a₁ + (3-1)d
a₃ = -5 + 2d
a₃ = -5 + 2(2) ∵ d = 2
a₃ = -5 + 4
a₃ = -1
Thus,
a₂ = -3
a₃ = -1
Thus, the sequence becomes:
-5, -3, -3, 1
