A torque of 12 N • m is applied to a solid, uniform disk of radius 0.50 m, causing the disk to accelerate at 5.7 rad/s2. What is
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At the top of the height, the velocity is zero and acceleration is negative of acceleration due to gravity ( i.e ).
The time of the ball in air is 3.2 s, so ascending time is .
Therefore from kinematic equation,
Substituting the values we get,
, Here v = 0 at top.
Now from equation,
, here h is the height .
So,
.
Thus, the ball reached at its maximum height of 12.48 m.