Answer:
the moment of force is 25 Nm.
Explanation:
Given;
weight of the book, F = 50 N
distance through which his hand was stretched, d = 50 cm = 0.5 m
The moment of force is calculated as;
moment of force = F x r
moment of force = 50 N x 0.5 m
moment of force = 25 Nm
Therefore, the moment of force is 25 Nm.
Answer:
m = 3.75 [kg]
Explanation:
We must remember that momentum is defined as the product of mass by Velocity, therefore it can be represented by means of the following equation.
where:
P = momentum = 93.75 [kg*m/s]
m = mass [kg]
v = velocity = 25 [m/s]
Now replacing, we can clear the mass:
![P=m*v\\m=P/v\\m=93.75/25\\m=3.75 [kg]](https://tex.z-dn.net/?f=P%3Dm%2Av%5C%5Cm%3DP%2Fv%5C%5Cm%3D93.75%2F25%5C%5Cm%3D3.75%20%5Bkg%5D)
Answer:
It ultimately helps you focus on your long-term goals
Explanation:
From conservation of momentum, the ram force can be calculated similarly to rocket thrust:
F = d(mv)/dt = vdm/dt.
<span>In other words, the force needed to decelerate the wind equals the force that would be needed to produce it.
</span><span> v = 120/3.6 = 33.33 m/s
</span><span> dm/dt = v*area*density
</span> dm/dt = (33.33)*((45)*(75))*(1.3)
dm/dt = <span>
146235.375 </span><span>kg/s
</span><span> F = v^2*area*density
</span> F = (33.33)^2*((45)*(75))*(1.3) = <span>
<span>4874025 </span></span><span>N
</span> This differs by a factor of 2 from Bernoulli's equation, which relates velocity and pressure difference in reference not to a head-on collision of the fluid with a surface but to a fluid moving tangentially to the surface. Also, a typical mass-based drag equation, like Bernoulli's equation, has a coefficient of 1/2; however, it refers to a body moving through a fluid, where the fluid encountered by the body is not stopped relative to the body (i.e., brought up to its speed) like is the case in this problem.
<span>d = 950 m - 4.9t^2 m
The distance an object moves under constant acceleration is
d = 0.5at^2
where
d = distance
a = acceleration
t = time.
Since we're falling and since we're starting at 950 m above ground, the formula becomes:
d = 950 m - 0.5at^2
Substituting known values, and simplifying gives us
d = 950 m - 0.5*9.8 m/s^2 * t^2
d = 950 m - 4.9 m/s^2 * t^2
Since time is in seconds, we can cancel out the seconds in the units, getting
d = 950 m - 4.9t^2 m</span>
