The best answer is C) total mass of the team.
In tug of war, the mass of each team is a critical factor in determining which side wins. The team with greater mass will require greater force to move, and also is likely able to exert greater force on the other team due to the correlation between strength and mass.
Answer:
Bromine
Explanation:
because it is present in 17th group that gives valence electrons as 7 in its last orbit
Answer:
The work done in pulling the bucket to the top of the well is 3,360 ft-lb
Explanation:
Given
Weight = 6 lb
Depth = 80ft
Weight of Water = 40lb
Rate = 2ft/s
Leak Rate = 0.2ft/s
Calculating Workdone to lift the bucket
Work = Force * Distance
Work = 6 * 80
Work = 480ft-lb
At time t, the bucket is xi = 2t above the original depth of 80ft.
t = ½xi
But it now holds 40lb - 0.2t lb of water
= 40 - 0.2(½xi)
= 40 - 0.1xi.
This is the size of the water when it is x ft above the original depth.
To move this amount of water, we need (40 - 0.1xi)∆x
So, W = ∫(40 - 0.1xi)∆x {1,n}
Where n = 80
W = ∫(40 - 0.1x)dx {0,80}
W = 40x - ½(0.1x²) {0,80}
W = 40x - x²/20 {0,80}
W = 40(80) - 80²/20
W = 3200 - 320
W = 2880 ft-lb
The work done in pulling the bucket to the top of the well = 2880 + 480
= 3,360 ft-lb
The initial temperature of the metal bolt is 80.8 °C
We'll begin by calculating the heat absorbed by the water.
- Mass of water (M) = 0.15 Kg
- Initial temperature (T₁) = 21 °C
- Final temperature (T₂) = 25 °C
- Change in temperature (ΔT) = T₂ – T₁ = 25 – 21 = 4 °C
- Specific heat capacity of water (C) = 4184 J/KgºC
Q = MCΔT
Q = 0.15 × 4184 × 4
Q = 2510.4 J
Finally, we shall determine the initial temperature of the metal bolt.
- Heat absorbed by water = 2510.4 J
- Heat released by metal (Q) = –2510.4 J
- Mass of metal (M) = 0.050 Kg
- Final temperature (T₂) = 25 °C
- Specific heat capacity of metal (C) = 899 J/Kg°C
- Initial temperature (T₁) =?
Q = MC(T₂ – T₁)
–2510.4 = 0.050 × 899 (25 – T₁)
–2510.4 = 44.95 (25 – T₁)
Clear bracket
–2510.4 = 1123.75 – 44.95T₁
Collect like terms
–2510.4 – 1123.75 = –44.95T₁
–3634.15 = –44.95T₁
Divide both side by –44.95
T₁ = –3634.15 / –44.95
T₁ = 80.8 °C
Thus, the initial temperature of the metal is 80.8 °C.
Learn more about heat tranfer:
brainly.com/question/26034272
Kinematics is the branch of physics and a subdivision of classical mechanics concerned with the geometrically possible motion of a body or system of bodies without consideration of the forces involved. :)
