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photoshop1234 [79]
3 years ago
10

Which statement correctly explains molecular motion in different states of matter using the kinetic theory?

Physics
1 answer:
Gelneren [198K]3 years ago
8 0

the answer is the second one

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The entropy of an isolated system must be conserved, so it never changes.a. Trueb. Fasle
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Answer:

B: False

Explanation:

The second law of thermodynamics states that: the entropy of an isolated system will never decrease because isolated systems always tend to evolve towards thermodynamic equilibrium which is a state with maximum entropy.

Thus, it means that the entropy change will always be positive.

Therefore, the given statement in the question is false.

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The chandra x-ray observatory is used to study _____.
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At what location in a circuit is the electrical potential energy the greatest
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It's not the potential energy.  It's just the potential.

It's greatest at the positive terminal of the battery or power supply.


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4 years ago
Why are plants generally green?
e-lub [12.9K]

The correct answer is option D, "The pigment chlorophyll reflects green light waves"

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7 0
3 years ago
An electric motor spins at 1000 rpm and is slowing down at a rate of 10 t rad/s2 ; where t is measured in seconds. (a) If the mo
REY [17]

Answer:

a) The tangential component of acceleration at the edge of the motor at  t = 1.5\,s is -1.075 meters per square second.

b) The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

Explanation:

The angular aceleration of the electric motor (\alpha), measured in radians per square second, as a function of time (t), measured in seconds, is determined by the following formula:

\alpha = -10\cdot t\,\left[\frac{rad}{s^{2}} \right] (1)

The function for the angular velocity of the electric motor (\omega), measured in radians per second, is found by integration:

\omega = \omega_{o} - 5\cdot t^{2}\,\left[\frac{rad}{s} \right] (2)

Where \omega_{o} is the initial angular velocity, measured in radians per second.

a) The tangential component of aceleration (a_{t}), measured in meters per square second, is defined by the following formula:

a_{t} = R\cdot \alpha (3)

Where R is the radius of the electric motor, measured in meters.

If we know that R = 7.165\times 10^{-2}\,m, \alpha = 10\cdot t and t = 1.5\,s, then the tangential component of the acceleration at the edge of the motor is:

a_{t} = (7.165\times 10^{-2}\,m)\cdot (-10)\cdot (1.5\,s)

a_{t} = -1.075\, \frac{m}{s^{2}}

The tangential component of acceleration at the edge of the motor at  t = 1.5\,s is -1.075 meters per square second.

b) If we know that \omega_{o} = 104.720\,\frac{rad}{s} and \omega = 26.180\,\frac{rad}{s}, then the time needed is:

26.180\,\frac{rad}{s} = 104.720\,\frac{rad}{s}-5\cdot t^{2}

5\cdot t^{2} = 104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}

t^{2} = \frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}  }{5}

t = \sqrt{\frac{104.720\,\frac{rad}{s}-26.180\,\frac{rad}{s}  }{5} }

t \approx 3.963\,s

The electric motor will take approximately 3.963 seconds to decrease its angular velocity by 75 %.

8 0
3 years ago
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