If you are given only delta G? Not enough information, unless you also have a big chart of a ton of heats of formation and other stuff
Answer:
46.73ºC
Explanation:
The sheets will change heat to achieve the thermal equilibrium, it means that they'll have the same final temperature (T). The heat (q) must be equal for both in magnitude, but with opposite directions.
The heat flows from the higher temperature for the lower, so it flows from the iron (Fe) to the gold (Au) sheet:
qAu = -qFe
The heat can be calculated by the equation:
q = m*cp*ΔT
Where m is the mass, cp is the specif heat capacity, and ΔT the temperature variation.
CpAu = 0.129 J/gºC
CpFe = 0.444 J/gºC
10.2*0.129*(T - 19.4) = -19.9*0.444*(T - 50.8)
1.3158*(T - 19.4) = -8.8356*(T - 50.8)
1.3158T - 25.52652 = -8.8356T + 448.84848
1.3158T + 8.8356T = 448.84848 + 25.52652
10.1514T = 474.375
T = 46.73ºC
It is a <u><em>chemical compound</em></u> formed with a metal (mainly positive cations) with oxygen.
It is formed through the air as they react in the air together.
They are also BASES - ALKALINE (so neutralise acids)
Science is the knowledge and study of the structure and behaviour of the physical and natural world, whiles technology is more about the TOOLS used and applied to study the science. They are related because technology is beneficial in science, like in experiments or investigations.
Example:
Science is - structure of a leaf.
Technology is - microscope.
Hope I helped!
Because 25% is half of 0.5 and the half life of
is given as 5,715, the time it takes to reach this amount should just be double the half life: 11430 years.
However, in other cases the problem may not have easy numbers, so below is a more mathematical approach.
The half life formula is
.
Solving for t gives:
![t=\frac{h*\ln(\frac{A}{A_0} )}{\ln(\frac{1}{2} )}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7Bh%2A%5Cln%28%5Cfrac%7BA%7D%7BA_0%7D%20%29%7D%7B%5Cln%28%5Cfrac%7B1%7D%7B2%7D%20%29%7D)
Given information:
![A=0.25A_0\\h=5715\text{ yrs}](https://tex.z-dn.net/?f=A%3D0.25A_0%5C%5Ch%3D5715%5Ctext%7B%20yrs%7D)
Plug in given values and solve for t.
![t=\frac{5715 *\ln(0.25) }{\ln(\frac{1}{2} )} =11430 \text{ yrs}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B5715%20%2A%5Cln%280.25%29%20%7D%7B%5Cln%28%5Cfrac%7B1%7D%7B2%7D%20%29%7D%20%3D11430%20%5Ctext%7B%20yrs%7D)
With correct significant figures, this would be 11000 years.