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3 years ago

what will most likely be observed when sulfur powder and iron powder are mixed together and then add water

Chemistry

2 answers:

Dovator [93]3 years ago

5 0

Sulfur will float and iron will sink because each will retain its properties

stepladder [879]3 years ago

4 0

Answer:

When Iron powder and Sulfur powder are mixed, no chemical reaction will occur, so you will see a physical change. The heterogeneous mixture resulting from mixing Iron powder with Sulfur powder could be easily separated using a magnet. When heating both compounds; however, it is possible to observe a chemical change as Iron Sulfide is formed. This product looks dark, shiny and is solid.

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Two different bromide solutions are mixed with each other: Solution 1 is an aqueous solution of 4.85 g aluminum bromidein 150. m

erma4kov [3.2K]

Answer:

M=0.380 M.

Explanation:

Hello there!

In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:

$n_{Br^-}^{in\ AlBr_3}=4.85 gAlBr_3*\frac{1molAlBr_3}{266.69gAlBr_3}*\frac{3molBr^-}{1molAlBr_3} =0.05456molBr^-\\\\n_{Br^-}^{in\ ZnBr_2}=7.75gZnBr_2*\frac{1molZnBr_2}{225.22gZnBr_2}*\frac{2molBr^-}{1molZnBr_2} =0.06882molBr^-$

Now, we compute the total moles of bromide:

$n_{Br^-}=0.05456mol+0.06882mol\\\\n_{Br^-}=0.12338mol$

Then, the total volume in liters:

$150mL+175mL=325mL*\frac{1L}{1000mL} \\\\=0.325L$

Therefore, the concentration of total bromide is:

$M=\frac{0.12338mol}{0.325L}\\\\M=0.380M$

Best regards!

8 0

2 years ago

17 POINTS!!! JUST DO A B C D PLS!!!! PLS DONT COMMENT IF YOU DONT KNOW IT ITS DUE BY TOMORROW AND I CANT KEEP WASTING POINTS PLS

dimulka [17.4K]

Answer:

A B C D E

Explanation:

7 0

2 years ago

What is the concentration in molarity of S2O32- (aq) in a solution prepared by mixing 150 mLmL of 0.149 MM Na2S2O3 (aq) with eno

Artist 52 [7]

Answer:

0.0890 M

Explanation:

Since the concentration of KCl is irrelevant in this case, the concentration of Na2S2O3 can be determined using a simple dilution equation:

C1V1 = C2V2, where C1 = 0.149 M, V1 = 150 mL, V2 = 250 mL

C2 = 0.149 x 150/250

= 0.089 M

To determine the concentration of S2O32- (aq), consider the equation:

$Na_2S_2O_3 => 2Na^+_{(aq)} + S_2O^2^-_3_{(aq)}$

The concentration of Na2S2O3 and S2O32- (aq) is 1:1

Hence, the concentration in molarity of S2O32- (aq) is 0.089 M.

To 3 significant figures = 0.0890 M

7 0

2 years ago

A picture of a patient’s lung showed it to be shriveled and darker than usual.

Strike441 [17]

Answer:

Smoking

Explanation:

It has been proven time and time again to ruin lungs, effectively shortenning ones lifespan.

3 0

2 years ago

Read 2 more answers

Calculate the number of moles of a gas if it occupies a volume of 4dm at 10atm and _200°c.

Rina8888 [55]

The number of moles of a gas if it occupy a volume of 4dm at 10 atm and - 200 c is 6.67 moles

calculation
by use of ideal gas equation
that is PV =nRT
where P(pressure) = 10 atm
V( volume) = 4dm^3 = 4L
n(number of moles) =?
R(gas constant) = 0.0821 L.atm/mol.K
T = -200 +273 = 73 K

make n the formula of the subject n = PV/RT

n is therefore = (10 atm x 4l)/(0.0821 L.atm/mol.K x 73 K) = 6.67 moles

5 0

2 years ago