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3 years ago

what will most likely be observed when sulfur powder and iron powder are mixed together and then add water

Chemistry

2 answers:

Dovator [93]3 years ago

5 0

Sulfur will float and iron will sink because each will retain its properties

stepladder [879]3 years ago

4 0

Answer:

When Iron powder and Sulfur powder are mixed, no chemical reaction will occur, so you will see a physical change. The heterogeneous mixture resulting from mixing Iron powder with Sulfur powder could be easily separated using a magnet. When heating both compounds; however, it is possible to observe a chemical change as Iron Sulfide is formed. This product looks dark, shiny and is solid.

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A. How well a current will flow in a material and it's measured in volts.

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Why are covalent bonds between hydrogen and nitrogen or oxygen polar?

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Answer:

The answer to your question is below

Explanation:

Covalent bonds are bonds between to atoms that share a pair of electrons, there are three kinds of covalent bonds but I'll describe only two:

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Covalent polar bond: is a covalent bond between 2 elements of different elements, for example: hydrogen and chlorine or nitrogen, they are polar because on of the element that form it is smaller than the other one, then a partial positive and a partial negative charge is formed.

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3 years ago

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lakkis [162]

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3 years ago

Given the following data:N2(g) + O2(g)→ 2NO(g), ΔH=+180.7kJ2NO(g) + O2(g)→ 2NO2(g), ΔH=−113.1kJ2N2O(g) → 2N2(g) + O2(g), ΔH=−163

statuscvo [17]

Answer:

ΔH = +155.6 kJ

Explanation:

The Hess' Law states that the enthalpy of the overall reaction is the sum of the enthalpy of the step reactions. To do the addition of the reaction, we first must reorganize them, to disappear with the intermediaries (substances that are not presented in the overall reaction).

If the reaction is inverted, the signal of the enthalpy changes, and if its multiplied by a constant, the enthalpy must be multiplied by the same constant. Thus:

N₂(g) + O₂(g) → 2NO(g) ΔH = +180.7 kJ

2NO(g) + O₂(g) → 2NO₂(g) ΔH = -113.1 kJ

2N₂O(g) → 2N₂(g) + O₂(g) ΔH = -163.2 kJ

The intermediares are N₂ and O₂, thus, reorganizing the reactions:

N₂(g) + O₂(g) → 2NO(g) ΔH = +180.7 kJ

NO₂(g) → NO(g) + (1/2)O₂(g) ΔH = +56.55 kJ (inverted and multiplied by 1/2)

N₂O(g) → N₂(g) + (1/2)O₂(g) ΔH = -81.6 kJ (multiplied by 1/2)

------------------------------------------------------------------------------------

N₂O(g) + NO₂(g) → 3NO(g)

ΔH = +180.7 + 56.55 - 81.6

ΔH = +155.6 kJ

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3 years ago

If the products of a certain reaction are favored (i.e., the ΔG value of the reaction is negative), one would expect a significa

Over [174]

Answer:

positive H and negative S

Explanation:

For a reaction to be spontaneous, the absolute best combination is a negative Delta H and a positive Delta S. When they are both positive, the reaction is only spontaneous at higher temperatures. When they are both negative, the reaction is only spontaneous at lower temperatures. and again if a catalyst is added to the reaction, the activation energy is lowered because a lower-energy transition state is formed. The catalyst does not affect the energy of the reactants or products (and thus does not affect ΔG).

So from these discussions

Ea does not affect G value at all (whether +Ea or -Ea).

And for product to be formed the reaction should be spontaneous, where H is negative and S positive else the reaction will yield low product.

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