The answer is 1) gained
Always <span><span>think "into" for "endo" (energy goes in), and "exit" for "exo" (energy is released).</span> </span>
Hope it helps ^-^
B. condenses is the answer
Answer:
0.373 moles of ammonium carbonate
Explanation:
To solve this question we must find the molar mass of ammonium carbonate. With the molar mass and the mass we can find its moles, as follows:
(NH₄)₂CO₃ contains: 2 moles N, 8 moles H, 1 mole C, 3 moles O. Molar mass:
2N = 14.0g/mol*2 = 28.0
8H = 1.0g/mol*8 = 8.0
1C = 12.0g/mol*1 = 12.0
3O = 16.0g/mol*3 = 48.0
Molar mass: 28.0 + 8.0 + 12.0 + 48.0 = 96.0g/mol
The moles of ammonium carbonate in 35.8g are:
35.8g * (1mol / 96.0g) =
<h3>0.373 moles of ammonium carbonate</h3>
Missing question:
Suppose Gabor, a scuba diver, is at a depth of 15 m. Assume that:
1. The air pressure in his air tract is the same as the net water pressure at this depth. This prevents water from coming in through his nose.
2. The temperature of the air is constant (body temperature).
3. The air acts as an ideal gas.
4. Salt water has an average density of around 1.03 g/cm^3, which translates to an increase in pressure of 1.00 atm for every 10.0 m of depth below the surface. Therefore, for example, at 10.0 m, the net pressure is 2.00 atm.
T = 37°C = 310 K.
p₁ = 2,5 atm = 253,313 kPa.
p₂ = 1 atm = 101,325 kPa.
Ideal gas law: p·V = n·R·T.
n₁ = 253,313 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₁ = 0,589 mol.
n₂ = 101,325 kPa · 6 L ÷ 8,31 J/mol·K · 310 K.
n₂ = 0,2356 mol.
Δn = 0,589 mol - 0,2356 mol = 0,3534 mol.
