1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
MatroZZZ [7]
2 years ago
11

Covalent bond of N and S

Chemistry
1 answer:
Mademuasel [1]2 years ago
8 0

Answer:

Covalent bond between identical atoms

Covalent bonds occur between identical atoms or between different atoms whose difference in electronegativity is insufficient to allow transfer of electrons to form ions. ... The two hydrogen atoms are attracted to the same pair of electrons in the covalent bond.

You might be interested in
elements on the right side of the periodic table differ from the elements on the left side in that elements on the right side
yarga [219]

Element  on the right side  of the periodic  table  differ from the elements on  the left side  in that elements on the <em>right  side  are non   metallic  and tends to be gases at room  temperature.</em>


<em>  </em><u>Explanation</u>

In the periodic table there element in  the right side , left side and those  which are in between.

  •  Example of element  in the right side is  fluorine  chlorine, neon, Argon   among others.
  • This element have higher  effective nuclear  charges   and  stabilize electrons more effectively.
  • there electrostatic  intermolecular  forces  are generally weak  therefore they  exist in  liquid or gaseous state.
7 0
2 years ago
The function of a specific enzyme is mostly determined by its
galben [10]

Answer:

What does the shape of an enzyme determine? The shape of the enzyme determines which chemical reaction it will speed up. -The region on an enzyme that the substrate fits into. ... The active site of an enzyme only fits one type of substrate molecule.

Explanation:

7 0
2 years ago
A sample of Francium-212 will decay to one sixteenth of its original amount after 80 minutes. What is the half-life of Francium-
lbvjy [14]

20 minutes.

The sample would lose one half the quantity of francium in each half-life.

1/16 = 1/2^{4} = 1/2 \times1/2 \times1/2 \times1/2

Thus a mass decrease by a factor of 16 would correspond to a period of four half-lives. It took 80 minutes for the sample to lose all these francium, therefore

t_{1/2} = 80/4 = 20 minutes.

6 0
3 years ago
HELP!!! I WILL RATE BRAINLIEST!!!
ad-work [718]

Answer:

it D yo

Explanation:

7 0
3 years ago
Which of the following statements are part of the kinetic molecular theory ?
Zielflug [23.3K]

Answer: The average kinetic energy is proportional to the absolute temperature of the gas. Gas particles are in random motion. Gas particles have no volume. And the collisions between gas particles are elastic.

Explanation: I heard this question before, I think. Hope this helps!

7 0
3 years ago
Other questions:
  • If I have 12.0 volume of gas at pressure of 1.10 and temperature of 200k, what is the number of moles? (R=8314)
    13·1 answer
  • Which component of the atom has the least mass HELLLP
    6·2 answers
  • Which of the following statements is FALSE? A. Air temperatures over the ocean remain fairly constant throughout a 24-hour cycle
    5·2 answers
  • How many grams of KBr are required to make 350. mL of a 0.115 M KBr solution?
    6·2 answers
  • What is a real life example of Charles’ law?
    15·1 answer
  • Which term describes the information that a scientist gathers during an investigation? Data, hypothesis, observation, variable a
    7·1 answer
  • How does changing the surface area increase the reaction rate of a chemical change
    13·1 answer
  • The balanced net ionic equation for precipitation of CaCO3 when aqueous solutions of Li2CO3 and CaCl2 are mixed is
    13·1 answer
  • How do covalent bonds form neutral compounds?
    9·1 answer
  • Cuánto es aproximadamente 29, 029 pies en millas
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!