Answer:
D is the answer. The graph was reflected across the y-axis, and shifted 1 unit downwards.
Step-by-step explanation:
Count the number of spaces to D, then to D'. They are the same (besides one being negative). A'B'C'D' was then shifted down 1 unit, which is why it is lower than shape ABCD.
Angles are the space between intersecting lines, and they are measured in degrees or radians
The measure of angle ABC is y + x
<h3>How to determine angle ABC</h3>
The given parameters are:
ABD=y,
DBC=x,
EFH=y,
EFG=x
PQS = SQR = x
To determine the measure of angle ABC, we make use of angle ABD and angle DBC
Note that angle ABD and angle DBC have common vertices at points B and D
So, we have:
ABC = ABD + DBC
Substitute known values
ABC = y + x
Hence, the measure of angle ABC is y + x
Read more about angle measures at:
brainly.com/question/17972372
Since sin(2x)=2sinxcosx, we can plug that in to get sin(4x)=2sin(2x)cos(2x)=2*2sinxcosxcos(2x)=4sinxcosxcos(2x). Since cos(2x) = cos^2x-sin^2x, we plug that in. In addition, cos4x=cos^2(2x)-sin^2(2x). Next, since cos^2x=(1+cos(2x))/2 and sin^2x= (1-cos(2x))/2, we plug those in to end up with 4sinxcosxcos(2x)-((1+cos(2x))/2-(1-cos(2x))/2)
=4sinxcosxcos(2x)-(2cos(2x)/2)=4sinxcosxcos(2x)-cos(2x)
=cos(2x)*(4sinxcosx-1). Since sinxcosx=sin(2x), we plug that back in to end up with cos(2x)*(4sin(2x)-1)
Answer:
A i believe
Step-by-step explanation:
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