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Alexandra [31]
2 years ago
7

Find the value of k so that the remainder is 1 when x^3+5x^2+kx-8 is divided by (x-3) K=

Mathematics
1 answer:
Brut [27]2 years ago
5 0

By the remainder theorem, the remainder upon dividing x^3+5x^2+kx-8 by x-3 is given by the value of this expression when <em>x</em> = 3 :

3^3 + 5\cdot3^2 + 3k - 8 = 1

Solve for <em>k</em> :

27 + 45 + 3k - 8 = 1 \\\\ 3k = -63 \\\\ \boxed{k = -21}

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